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面临以下问题：我有一个 wsdl 文件，用于通过 SOAP 通信我的服务和 CRM。请求的主体是通过从 wsdl 配置 java 文件来填充的。但是标题必须手动编写。我正在使用以下技术发送我的请求：

 final Map<String, String> gateValues = new HashMap<>();
    final String username = Objects.requireNonNull(config).getSoapconf().getUsername();
    final String password = Objects.requireNonNull(config).getSoapconf().getPassword();
    final String webServices = Objects.requireNonNull(config).getSoapconf().getSessionType();
    gateValues.put("UsernameToken", username);
    gateValues.put("PasswordText", password);
    gateValues.put("SessionType", webServices);
    GetInput rq = new GetInput();
    rq.setMyParam(param);
    log.info("Requesting {}", param);
    try {
        GetOutput client = (GetOutput) getWebServiceTemplate().marshalSendAndReceive(rq, (message) -> {
            if (message instanceof SaajSoapMessage) {
                SaajSoapMessage saajSoapMessage = (SaajSoapMessage) message;
                SOAPMessage soapMessage = saajSoapMessage.getSaajMessage();
                SOAPPart soapPart = soapMessage.getSOAPPart();

                try {
                    SOAPEnvelope soapEnvelope = soapPart.getEnvelope();
                    SOAPHeader soapHeader = soapEnvelope.getHeader();

                    gateValues.forEach((key, value) -> {
                        try {
                            Name headerElementName = soapEnvelope.createName(
                                    key,
                                    PREFIX,
                                    NAMESPACE
                            );
                            System.out.println(headerElementName.getLocalName() + "\n" + headerElementName.getQualifiedName());
                            SOAPHeaderElement soapHeaderElement = soapHeader.addHeaderElement(headerElementName);
                            soapHeaderElement.setTextContent(value);
                        } catch (SOAPException e) {
                            // error handling
                        }
                    });

                    soapMessage.saveChanges();
                    soapMessage.writeTo(System.out);
                    System.out.println(soapEnvelope.getHeader());
                } catch (SOAPException e) {
                    System.out.println();
                }
            }
        });
        return client;
    } catch (Exception e) {
        ExceptionUtils.getStackTrace(e);
    }

已添加最后一个捕获以查找错误。从 WebServiceTemplate 类的 doSendAndReceive 方法中丢弃错误 org.springframework.ws.soap.client.SoapFaultClientException。

  <SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
        <SOAP-ENV:Header>
            <PasswordText xmlns="http://***.com/services">myPass</PasswordText>
            <SessionType xmlns="http://****.com/services">mySessionType</SessionType>
            <UsernameToken xmlns="http://***.com/services">myUsName</UsernameToken>
        </SOAP-ENV:Header>
        <SOAP-ENV:Body><ns2:Get_Input xmlns:ns2="http://***.com/UI" xmlns:ns3="http://***.com/xml/%20External">
            <ns2:param>238068014416</ns2:param>
        </ns2:Get_Input>
        </SOAP-ENV:Body>
        </SOAP-ENV:Envelope>

什么不见​​了？为什么 SOAPUI - 它是有效的。客户端请求是按照Add SoapHeader to org.springframework.ws.WebServiceMessage的最后一个答案的示例进行的

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