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我正在尝试查询 sqlite，它给了我电表的消耗量。如果我想创建一个简单的示例：

CREATE TABLE datalog (
 id INTEGER PRIMARY KEY AUTOINCREMENT,
 tstamp DATETIME DEFAULT CURRENT_TIMESTAMP,
 rValue REAL);


INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 00:00:01', 25.1);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 00:15:01', 26.2);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 00:30:01', 27.5);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 00:45:01', 28.8);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 01:00:01', 29.4);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 01:15:01', 30.2);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 01:30:01', 31.5);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 01:45:01', 32.2);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 02:00:01', 33.9);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 02:15:01', 35.2);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 02:30:01', 36.1);
INSERT INTO datalog (tstamp,rValue) VALUES ('2020-01-02 15:30:01', 80.4);

我想为此表编写一个查询，通过选择今天的第一个读取值和日期时间（如果我们假设今天是 2020 年 1 月 2 日）以及今天的最后读取值和日期时间，我可以得到电表的消耗量并给出下表

startDT             | startValue | lastDT              | lastValue | consumption
2020-01-02 00:00:01 | 25.1       | 2020-01-02 15:30:01 | 80.4      | 55.3
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2 回答 2

0

无需交叉连接 2 个子查询。
您可以使用窗口函数来做到这一点：

SELECT DISTINCT
       MIN(tstamp) OVER () startDT,
       FIRST_VALUE(rValue) OVER (ORDER BY tstamp) startValue,
       MAX(tstamp) OVER () lastDT,
       FIRST_VALUE(rValue) OVER (ORDER BY tstamp DESC) lastValue,
       FIRST_VALUE(rValue) OVER (ORDER BY tstamp DESC) - FIRST_VALUE(rValue) OVER (ORDER BY tstamp) consumption
FROM datalog
WHERE date(tstamp) = CURRENT_DATE
于 2021-05-26T12:49:45.487 回答
0

没关系，我通过更多研究解决了它

答案是在 FROM 子句中使用多个子查询

SELECT
startData.tstamp AS 'starttime',
startData.rValue AS 'startvalue',
lastData.tstamp AS 'lasttime',
lastData.rValue AS 'lastvalue',
(lastData.rValue-startData.rValue) AS 'consumption'
FROM (  SELECT tstamp, rValue
        FROM datalog
        WHERE   tstamp>= datetime('now','start of day')
        ORDER BY tstamp ASC LIMIT 1) startData,
     (  SELECT tstamp,rValue
        FROM datalog
        WHERE tstamp>= datetime('now','start of day')
        ORDER BY tstamp DESC LIMIT 1) lastData;
于 2021-05-26T09:20:35.000 回答