7

我正在创建一个 Django 应用程序,其中所有模型都可以按照用户设置的顺序相互关联。我正在使用 GenericForeignKeys 设置所有这些。更重要的是,我需要能够支持这些类型的关系/管理的多个集合。所以一个对象可以有多个相关对象的集合。

有谁知道这种情况下一个好的 GenericForeignKey 小部件?最好是填充管理表单的自动完成搜索,因为我最终可能会拥有大量对象。

这是我的应用程序的代码,可以更好地理解我的意思。

from django.contrib import admin
from django.contrib.contenttypes import generic
from django.contrib.contenttypes.models import ContentType
from django.db import models
from django import forms


# Models
class Base(models.Model):
    title = models.CharField(max_length=255)

    class Meta:
        abstract = True

    def __unicode__(self):
        return self.title

class Related(Base):
    """ A generic relationship model for relating resources.
    """
    order = models.IntegerField(blank=True, null=True)
    limit = models.Q(model = 'Apple') | models.Q(model = 'Orange') | models.Q(model = 'Pear') 

    content_type = models.ForeignKey(ContentType, related_name="related_%(class)s")
    object_id = models.PositiveIntegerField(db_index=True)
    object = generic.GenericForeignKey()

    related_content_type = models.ForeignKey(ContentType, related_name="related_related_%(class)s", limit_choices_to = limit)
    related_object_id = models.PositiveIntegerField(db_index=True)
    related_object = generic.GenericForeignKey('related_content_type', 'related_object_id')

    class Meta:
        ordering = ('order',)
        abstract = True

    def __unicode__(self):
        return self.object.title

class FreshFruit(Related):
    pass

class OldFruit(Related):
    pass

class Apple(Base):
    pass

class Orange(Base):
    pass

class Pear(Base):
    pass

# Admin classes
class FreshFruitInline(generic.GenericStackedInline):
    model = FreshFruit
    extra = 1
    # Admin classes

class OldFruitInline(generic.GenericStackedInline):
    model = OldFruit
    extra = 1

class AppleAdmin(admin.ModelAdmin):
    inlines = [FreshFruitInline, OldFruitInline,]
admin.site.register(Apple, AppleAdmin)

class OrangeAdmin(admin.ModelAdmin):
    inlines = [FreshFruitInline, OldFruitInline,]
admin.site.register(Orange, OrangeAdmin)

class PearAdmin(admin.ModelAdmin):
    inlines = [FreshFruitInline, OldFruitInline,]
admin.site.register(Pear, PearAdmin)

我已经搜索和搜索,并找到了为多对多关系执行此操作的小部件,但对我的情况没有任何帮助。

感谢您花时间看这个。

4

1 回答 1

7

看看 Grappelli 的通用外键小部件,效果很好: django-grappelli/generic_2_2

于 2011-07-20T07:35:22.330 回答