ruby - 阵列半展平

Question

想要转换这个：

[["1", "2", "3"], ["4", "5", "6"]]

对此：

["1", "2", "3"], ["4", "5", "6"]

要传递给 Array.product()，第一个数组可以包含未知数量的其他数组。例如，给定的数组也可能是

[["1", "2", "3"], ["4", "5", "6"], ["7", "8", "9"]]

最终，我需要将论点传递为：

otherArray.product(["1", "2", "3"], ["4", "5", "6"], ["7", "8", "9"])

提前谢谢！

Answer 1

otherArray.product(*[["1", "2", "3"], ["4", "5", "6"], ["7", "8", "9"]]);

* 在参数列表中用于将数组内容解包到参数（如此处）或将参数打包到数组中，如“def mymethod（*args）”

参考：http ://www.justskins.com/forums/apply-method-to-array-17387.html

Answer 2

I think what would work for you is using Ruby's Array expansion:

a=[[1,2,3],[4,5,6]]
b=[1,2,3].product([1,2,3],[4,5,6])
c=[1,2,3].product(*a)
b == c #This should be true

Basically putting the asterisk (*) in front of the variable will expand all elements in the array into a list of arguments, which is what you want.

Answer 3

撇开最后一行代码不谈，其余部分似乎通过使用 0 索引来解决：

arr[0]