0

我有一个存储过程MATCH AGAINST，它最初返回按相关性排序的数据，这就是我想要的。但是，当我添加 aLEFT JOIN和 a secondMATCH AGAINST时，它现在从两者返回数据，但不再按相关性排序。它现在按 ID 自动排序。

从一个按相关性排序的表返回：

BEGIN
    SELECT
        dictionary.id,
        dictionary.`term`,
        dictionary.`definition`
    FROM itDictionary dictionary
    WHERE MATCH(dictionary.term, dictionary.definition)
    AGAINST(_query IN NATURAL LANGUAGE MODE);
END

从两个表返回，但以某种方式按 ID 排序：

BEGIN
    SELECT
        dictionary.id,
        dictionary.`term`,
        dictionary.`definition`,
        links.id,
        links.`name`,
        links.`url`
    FROM itDictionary dictionary
        LEFT JOIN itRelatedLinks links ON links.term_id = dictionary.id
    WHERE MATCH(dictionary.term, dictionary.definition)
    AGAINST(_query IN NATURAL LANGUAGE MODE)
        OR MATCH(links.name)
    AGAINST(_query IN NATURAL LANGUAGE MODE);
END

我接近了吗？

4

1 回答 1

1

You can do something like this

SELECT
    dictionary.id,
    dictionary.`term`,
    dictionary.`definition`,
    links.id,
    links.`name`,
    links.`url`
FROM itDictionary dictionary
    LEFT JOIN itRelatedLinks links ON links.term_id = dictionary.id
WHERE MATCH(dictionary.term, dictionary.definition)
AGAINST(_query IN NATURAL LANGUAGE MODE)
    OR MATCH(links.name)
AGAINST(_query IN NATURAL LANGUAGE MODE)
ORDER BY MATCH(dictionary.term, dictionary.definition)
AGAINST(_query IN NATURAL LANGUAGE MODE)
    + MATCH(links.name)
AGAINST(_query IN NATURAL LANGUAGE MODE);

It would add the score of both and have so a combined score to sort by

Of xourse you can add a factor to each score to prioritise one

于 2021-05-10T13:46:59.980 回答