我尝试通过方法句柄将方法链接在一起,其中一些来自泛型类型。如果一个函数返回一个泛型类型,我必须为 MethodType 指定 Object.class,但我看不到将它转换回泛型类型参数类型的简单方法。在大多数情况下,这没有问题,因为invoke 似乎会自动转换它们,但我必须创建可以使用invokeExact 运行的mhs。没有简单的方法来使用方法句柄进行转换吗?
我的测试代码:
public static void main(String[] args) throws Throwable {
class Prefixer {
public static String prefix(String s) {
return "Number: " + s;
}
}
IntFunction<String> converter = Integer::toString;
var lookup = MethodHandles.lookup();
var prefixMH = lookup.findStatic(Prefixer.class, "prefix", MethodType.methodType(String.class, String.class));
var converterMH = lookup.findVirtual(IntFunction.class, "apply", MethodType.methodType(Object.class, int.class));
converterMH = converterMH.bindTo(converter);
/* Doesn't work because converter is a (int)Object and no (int)String
var mh = MethodHandles.filterArguments(prefixMH, 0, converterMH);
*/
/* Does work for invoke but not for invokeExact
var prefixCasted = MethodHandles.explicitCastArguments(prefixMH, MethodType.methodType(String.class, Object.class));
var mh = MethodHandles.filterArguments(prefixCasted, 0, converterMH);
*/
/* Does work for invoke but not for invokeExact */
var mh = MethodHandles.filterArguments(prefixMH, 0, converterMH.asType(MethodType.methodType(String.class, int.class)));
System.out.println(mh.invoke(12));
System.out.println(mh.invokeExact(42));
}