我是 OPA/Rego 的新手,我正在尝试编写一个策略来检查 Azure 网络安全组是否包含我在数组上定义的所有规则
package sample
default compliant = false
toSet(arr) = {x | x := arr[_]}
checkProperty(rule, index, propertySingular, propertyPlural) = true
{
object.get(input.properties.securityRules[index].properties, propertySingular, "") == object.get(rule, propertySingular, "")
count(toSet(object.get(input.properties.securityRules[index].properties, propertyPlural, [])) - toSet(object.get(rule, propertyPlural, []))) == 0
}
existRule(rule) = true
{
input.properties.securityRules[i].name == rule.name
input.properties.securityRules[i].properties.provisioningState == rule.provisioningState
input.properties.securityRules[i].properties.description == rule.description
input.properties.securityRules[i].properties.protocol == rule.protocol
checkProperty(rule, i, "sourcePortRange", "sourcePortRanges")
checkProperty(rule, i, "destinationPortRange", "destinationPortRanges")
checkProperty(rule, i, "sourceAddressPrefix", "sourceAddressPrefixes")
checkProperty(rule, i, "destinationAddressPrefix", "destinationAddressPrefixes")
input.properties.securityRules[i].properties.access == rule.access
input.properties.securityRules[i].properties.priority == rule.priority
input.properties.securityRules[i].properties.direction == rule.direction
}
compliant
{
rules := [
{
"name": "name1",
"provisioningState": "Succeeded",
"description": "description1",
"protocol": "*",
"sourcePortRange": "*",
"destinationPortRange": "53",
"destinationAddressPrefix": "*",
"access": "Allow",
"priority": 1,
"direction": "Inbound",
"sourceAddressPrefixes":
[
"xx.xx.xx.xx",
"xx.xx.xx.xx",
"xx.xx.xx.xx"
],
},
{
"name": "name2",
"provisioningState": "Succeeded",
"description": "description2",
"protocol": "*",
"sourcePortRange": "*",
"destinationPortRange": "54",
"sourceAddressPrefix": "*",
"access": "Allow",
"priority": 2,
"direction": "Outbound",
"destinationAddressPrefixes":
[
"xx.xx.xx.xx",
"xx.xx.xx.xx",
"xx.xx.xx.xx"
]
}
]
#checks
existRule(rules[i])
}
问题似乎是,existRule(rules[i])
如果其中一个规则匹配,则执行时返回 true,如果其他规则不匹配,则不要考虑如果我existRule(rules[i])
用existRule(rules[0])
or替换existRule(rules[1])
,它返回 true 或 false,具体取决于该位置上的规则是否匹配。
有没有办法获得existRule(rules[i])
数组所有元素的执行结果?
我已经尝试过result := [existRule(rules[i])]
了,但它只返回一个具有 true 的元素