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我正在尝试将数据拆分为训练和验证数据，为此我train_test_split从cuml.preprocessing.model_selection模块中使用。

但出现错误：

---------------------------------------------------------------------------
AttributeError                            Traceback (most recent call last)
<ipython-input-317-4e11838456ea> in <module>
----> 1 X_train, X_test, y_train, y_test = train_test_split(train_dfIF,train_y, test_size=0.20, random_state=42)

/opt/conda/lib/python3.7/site-packages/cuml/preprocessing/model_selection.py in train_test_split(X, y, test_size, train_size, shuffle, random_state, seed, stratify)
    454         X_train = X.iloc[0:train_size]
    455         if y is not None:
--> 456             y_train = y.iloc[0:train_size]
    457 
    458     if hasattr(X, "__cuda_array_interface__") or \

AttributeError: 'cupy.core.core.ndarray' object has no attribute 'iloc'

虽然我没有使用 iloc。

这是代码：

from cuml.preprocessing.model_selection import train_test_split

X_train, X_test, y_train, y_test = train_test_split(train_dfIF,train_y, test_size=0.20, random_state=42)

这train_dfIF是一个 cudf DataFrame 并且train_y是 cupy 数组。

4

1 回答 1

2

y如果您的X参数是数据框，则不能（当前）将数组传递给参数。我建议传递两个数据帧或两个数组，而不是一个一个。

from cuml.preprocessing.model_selection import train_test_split
import cudf
import cupy as cp

df = cudf.DataFrame({
    "a":range(5),
    "b":range(5)
})
y = cudf.Series(range(5))

# train_test_split(df, y.values, test_size=0.20, random_state=42) # fail
X_train, X_test, y_train, y_test = train_test_split(df, y, test_size=0.20, random_state=42) # succeed
X_train, X_test, y_train, y_test = train_test_split(df.values, y.values, test_size=0.20, random_state=42) # succeed
于 2021-05-03T14:30:23.750 回答