您需要使用 lua 自己编写过滤器:
apiVersion: networking.istio.io/v1alpha3
kind: EnvoyFilter
metadata:
name: custom-filter
namespace: some-namespace
spec:
workloadSelector:
labels:
istio: ingressgateway
configPatches:
- applyTo: HTTP_FILTER
match:
context: GATEWAY
listener:
filterChain:
filter:
name: "envoy.filters.network.http_connection_manager"
subFilter:
name: "envoy.extAuthz" # name of your ext_authz filter
patch:
operation: INSERT_AFTER
value:
name: envoy.custom-resp
typed_config:
"@type": "type.googleapis.com/envoy.extensions.filters.http.lua.v3.Lua"
inlineCode: |
function envoy_on_response(response_handle)
if response_handle:headers():get(":status") == "408" then
-- send message depending on your queue, eg via httpCall()
-- Overwrite status and body
response_handle:headers():replace(":status", "202")
else
-- get response body as jsonString
local body = response_handle:body()
local jsonString = tostring(body:getBytes(0, body:length()))
-- do something, eg replace secret by regex
jsonString = jsonString:gsub("(foo|bar)", "")
response_handle:body():set(jsonString)
end
end
请注意,您需要以某种方式处理队列的超时。
Lua 特使
httpCall
Lua 文档