如何就地构造可选聚合?看来我只能构造一个可选的单一事物,而不是可选的事物聚合。
#include <optional>
#include <iostream>
struct Unmovable
{
Unmovable(const Unmovable&) = delete;
Unmovable(Unmovable&&) = delete;
Unmovable& operator=(const Unmovable&) = delete;
Unmovable& operator=(Unmovable&&) = delete;
explicit Unmovable(const char* msg) {
std::cout << msg << '\n';
}
};
struct Things
{
Unmovable one;
Unmovable two;
};
int main(int argc, char* argv[]) {
const bool y = argc > 1 && argv[1][0] == 'y';
std::optional<Unmovable> optionalThing = y
? std::optional<Unmovable>{"works"}
: std::nullopt;
std::optional<Things> optionalThings = y
? std::optional<Things>{
#if ATTEMPT == 1
"jadda", "neida"
#elif ATTEMPT == 2
{"jadda", "neida"}
#elif ATTEMPT == 3
Things{"jadda", "neida"}
#elif ATTEMPT == 4
Unmovable{"jadda"}, Unmovable{"neida"}
#elif ATTEMPT == 5
{Unmovable{"jadda"}, Unmovable{"neida"}}
#elif ATTEMPT == 6
Things{Unmovable{"jadda"}, Unmovable{"neida"}}
#elif ATTEMPT == 7
std::in_place_t{}, "jadda", "neida"
#elif ATTEMPT == 8
std::in_place_t{}, {"jadda", "neida"}
#elif ATTEMPT == 9
std::in_place_t{}, Things{"jadda", "neida"}
#elif ATTEMPT == 10
std::in_place_t{}, Unmovable{"jadda"}, Unmovable{"neida"}
#elif ATTEMPT == 11
std::in_place_t{}, {Unmovable{"jadda"}, Unmovable{"neida"}}
#elif ATTEMPT == 12
std::in_place_t{}, Things{Unmovable{"jadda"}, Unmovable{"neida"}}
#endif
} : std::nullopt;
}