var path = "http://api.openweathermap.org/data/2.5/find?q=";
var city = "London";
var apiKey= "&appid=eb5eacd85411228f461a151003d9bf07";
var url = path + city+ apiKey;
function getTemp(){
fetch(url)
.then(response => response.json())
.then(data => {
var nameValue= data.name;
var tempr = data.main.temp;
document.querySelector("h1").innerHTML= nameValue;
document.querySelector("h2").innerHTML= tempr;
})}
getTemp();
运行此代码时出现错误。请帮我解决这里的问题。
