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我正在尝试将表单提交到 DB Browser Sqlite。我已经创建了一个表。我能够将数据存储到 Sqlite 中。但是，一旦我在提交按钮（submitclaim.html）中添加了一个执行确认弹出框的函数，就会显示这个错误

sqlite3.OperationalError: database is locked

当我尝试向表格提交表格时，它发生在以下行：

    c.execute("INSERT INTO SubmitClaim VALUES (?,?,?,?,?)", (depart, type, uploadre, amt, description)

这是我的 app.py

@app.route('/addrec', methods=['POST', 'GET'])
def addrec():
    if request.method == 'POST':

        depart = request.form['depart']
        type = request.form['type']
        uploadre = request.form['uploadre']

        amt = request.form['amt']
        description = request.form['description']

    conn = sql.connect(db_path)
    c = conn.cursor()

    c.execute(
        "INSERT INTO SubmitClaim VALUES (?,?,?,?,?)", (depart, type, uploadre, amt, description))

    conn.commit()

    c.execute("SELECT * FROM  SubmitClaim")
    print(c.fetchall())
    conn.close()

    return render_template('base.html', user=session["user"], version=msal.__version__)

这是我的 SubmitClaim.html

<div class="arrange3">
    <button onclick="myFunction()" type="submit" class="submit-button" name="save", value="save">Submit</button>
    <script>
    function myFunction() {
    confirm("Press a button!");
    }
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1 回答 1

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您只需在 DB Browser SQLITE 中关闭数据库并运行代码

于 2021-05-06T08:27:01.117 回答