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所以我最近从服务启动 jar 文件而不是首先进入相关目录的脚本切换。有没有办法确保使用 jar 文件的路径而不是服务启动它的位置?在应用程序内部,我使用下面的代码来获取正确的路径。

   try {
        Path p = Path.of(getClass().getProtectionDomain().getCodeSource().getLocation().toURI());

        workPath = p.getParent().toString();

        if( workPath.matches(".*[lib]")) { // Meaning used as a lib
            workPath = Path.of(workPath).getParent().toString();
        }
        settingsFile = Path.of(workPath, "settings.xml");
    } catch (URISyntaxException e) {
        Logger.error(e);
    }
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1 回答 1

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将您的工作路径存储为系统属性:

try {
    Path p = Path.of(getClass().getProtectionDomain().getCodeSource().getLocation().toURI());

    workPath = p.getParent().toString();
    if(workPath.matches(".*[lib]")) { // Meaning used as a lib
        workPath = Path.of(workPath).getParent().toString();
    }

    System.setProperty("tinylog.directory", workPath); // Set work path as system property
    settingsFile = Path.of(workPath, "settings.xml");
} catch (URISyntaxException e) {
    Logger.error(e);
}

使用 tinylog.properties 中的系统属性:

writer        = file
writer.file   = #{tinylog.directory}/log.txt
writer.format = {date: HH:mm:ss.SSS} {level}: {message}
于 2021-04-26T07:39:19.060 回答