我使用recycleView
with StaggeredGridLayoutManager
(列数为 3)。我需要确定当前单元格位于哪一列(按位置)。是否有可能做到这一点?请帮我。注意:我的单元格的高度不同(正方形或矩形)
问问题
83 次
2 回答
0
- 要从该位置获取Column:您可以使用该位置的余数/模数 3。
- 要从该位置获取行:您可以将其除以 3。
0 | 1 | 2
3 | 4 | 5
6 | 7 | 8
9 | 10 | 11
12 | 13 | 14
15 | 16 | 17
18 | 19 | 20
例子
for (int position = 0; position <= 20; position++) {
Log.d("LOG_TAG", "Item: " + position + " In Row: " + position / 3 + " In Col: " + position % 3);
}
日志:
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 0 In Row: 0 In Col: 0
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 1 In Row: 0 In Col: 1
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 2 In Row: 0 In Col: 2
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 3 In Row: 1 In Col: 0
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 4 In Row: 1 In Col: 1
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 5 In Row: 1 In Col: 2
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 6 In Row: 2 In Col: 0
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 7 In Row: 2 In Col: 1
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 8 In Row: 2 In Col: 2
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 9 In Row: 3 In Col: 0
2021-04-21 00:33:41.634 14288-14288/.. D/LOG_TAG: Item: 10 In Row: 3 In Col: 1
2021-04-21 00:33:41.635 14288-14288/.. D/LOG_TAG: Item: 11 In Row: 3 In Col: 2
2021-04-21 00:33:41.635 14288-14288/.. D/LOG_TAG: Item: 12 In Row: 4 In Col: 0
2021-04-21 00:33:41.635 14288-14288/.. D/LOG_TAG: Item: 13 In Row: 4 In Col: 1
2021-04-21 00:33:41.635 14288-14288/.. D/LOG_TAG: Item: 14 In Row: 4 In Col: 2
2021-04-21 00:33:41.635 14288-14288/.. D/LOG_TAG: Item: 15 In Row: 5 In Col: 0
2021-04-21 00:33:41.635 14288-14288/.. D/LOG_TAG: Item: 16 In Row: 5 In Col: 1
2021-04-21 00:33:41.635 14288-14288/.. D/LOG_TAG: Item: 17 In Row: 5 In Col: 2
2021-04-21 00:33:41.635 14288-14288/.. D/LOG_TAG: Item: 18 In Row: 6 In Col: 0
2021-04-21 00:33:41.635 14288-14288/.. D/LOG_TAG: Item: 19 In Row: 6 In Col: 1
2021-04-21 00:33:41.635 14288-14288/.. D/LOG_TAG: Item: 20 In Row: 6 In Col: 2
于 2021-04-20T22:25:34.360 回答
0
我认为您可以使用LayoutParams
子视图的 来确定跨度索引。一个带有 an 的例子ItemDecoration
可能看起来像这样(Kotlin):
class MyItemDecoration : RecyclerView.ItemDecoration() {
override fun getItemOffsets(outRect: Rect, view: View, parent: RecyclerView, state: RecyclerView.State) {
super.getItemOffsets(outRect, view, parent, state)
val params = view.layoutParams as StaggeredGridLayoutManager.LayoutParams
when(params.spanIndex) {
0 -> outRect.apply {
left = 20
right = 10
}
1 -> outRect.apply {
left = 10
right = 10
}
2 -> outRect.apply {
left = 10
right = 20
}
}
}
}
于 2022-02-01T13:33:02.157 回答