1

在 javafx 中键入自动完成时，如何在 codearea 中的当前插入符号位置创建一个列表视图？到目前为止，我找到了当前正在输入的单词，并查看该单词是否包含在数组中。这是我到目前为止的代码。先感谢您！

String[] keyphrases = new String[]{"int main(){\n}", "cout", "cin"};

((CodeArea)tabPane.getSelectionModel().getSelectedItem().getContent()).textProperty().addListener(new ChangeListener<String>()
                        {
                            @Override
                            public void changed(ObservableValue<? extends String> observableValue, String s, String s2) {
                                CodeArea sto = ((CodeArea)tabPane.getSelectionModel().getSelectedItem().getContent());
                                String curr = "";
                                String currFinal = "";
                                for (int i = sto.getAnchor(); i > 0; i--) {
                                    if (sto.getText().charAt(i) == '\n' || sto.getText().charAt(i) == ' ') {
                                        break;
                                    }else {
                                        curr += sto.getText().charAt(i);
                                    }
                                }
                                for (int i = curr.length()-1; i >= 0; i--) {
                                    currFinal += curr.charAt(i);
                                }
                                System.out.println(currFinal);
                                ArrayList<String> fil = new ArrayList<String>();
                                for (int i = 0; i < keyphrases.length; i++) {
                                    if (keyphrases[i].contains(currFinal)) {
                                        fil.add(keyphrases[i]);
                                    }
                                }
                                //display fil as listview in caret position?
                            } 
                        });
4

2 回答 2

1

如果您询问如何在插入符号位置显示 ListView，请检查以下方法。这是在当前插入符号位置显示 ListView 的一般高级方法。您可以根据您的要求关联逻辑和更改。

我相信这将为您提供有关如何处理的必要基础知识。话虽如此，还有许多其他更好的方法。

核心思想是依靠插入符节点（路径）边界，而不是进行复杂的计算来找到插入符在文本中的位置。

在此处输入图像描述

import javafx.application.Application;
import javafx.geometry.Bounds;
import javafx.geometry.Insets;
import javafx.scene.Node;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.control.ListView;
import javafx.scene.control.TextArea;
import javafx.scene.layout.Priority;
import javafx.scene.layout.Region;
import javafx.scene.layout.VBox;
import javafx.scene.shape.Path;
import javafx.stage.Popup;
import javafx.stage.Stage;

public class TextAreaCaretPositionDemo extends Application {
    private Bounds caretBoundsInScreen;
    private Node caret;

    @Override
    public void start(Stage stage) throws Exception {
        final VBox root = new VBox();
        root.setSpacing(10);
        root.setPadding(new Insets(10));
        final Scene sc = new Scene(root, 350, 200);
        stage.setScene(sc);
        stage.setTitle("TextArea Caret Position");
        stage.show();

        TextArea textArea = new TextArea() {
            @Override
            protected void layoutChildren() {
                super.layoutChildren();
                if (caret == null) {
                    final Region content = (Region) lookup(".content");
                    // Looking for the caret path node and add a listener to its bounds to keep track of its position in screen.
                    content.getChildrenUnmodifiable().stream()
                            .filter(node -> node instanceof Path)
                            .map(node -> (Path) node)
                            // Find a more better way to find the caret path node
                            .filter(path -> path.getStrokeWidth() == 1 && path.fillProperty().isBound() && path.strokeProperty().isBound())
                            .findFirst().ifPresent(path -> {
                        path.boundsInLocalProperty().addListener((obs, old, bounds) -> {
                            if (bounds.getWidth() > 0 && bounds.getHeight() > 0) {
                                caretBoundsInScreen = path.localToScreen(bounds);
                            }
                        });
                        caret = path;
                    });
                }
            }
        };
        textArea.setWrapText(true);
        VBox.setVgrow(textArea, Priority.ALWAYS);

        ListView<String> list = new ListView<>();
        list.setPrefSize(150,200);
        list.getItems().addAll("One","Two","Three");
        Popup popup = new Popup();
        popup.setAutoHide(true);
        popup.getContent().addAll(list);

        Button show = new Button("Show ListView");
        show.setOnAction(e->{
            popup.show(caret, caretBoundsInScreen.getMinX(), caretBoundsInScreen.getMaxY());
        });
        root.getChildren().addAll(show,textArea);

        textArea.setText("Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.");
    }
}
于 2021-04-19T23:37:01.313 回答
0

使用 Sai 的答案，我创建了自己的解决方案！

codeArea.textProperty().addListener(new ChangeListener<String>()
    {
        @Override
        public void changed(ObservableValue<? extends String> observableValue, String s, String s2) {
            
            
            String curr = "";
            String currFinal = "";
            for (int i = codeArea.getAnchor(); i > 0; i--) {
                if (codeArea.getText().charAt(i) == '\n' || codeArea.getText().charAt(i) == ' ') {
                    break;
                }else {
                    curr += codeArea.getText().charAt(i);
                }
            }
            
            for (int i = curr.length()-1; i >= 0; i--) {
                currFinal += curr.charAt(i);
            }
            
            if (currFinal != "") {
                ArrayList<String> fil = new ArrayList<String>();
                for (int i = 0; i < keyphrases.length; i++) {
                    if (keyphrases[i].contains(currFinal)) {
                        fil.add(keyphrases[i]);
                    }
                }
                System.out.println("Fil " + fil);
                if (popup != null) {
                    popup.hide();
                }
                if (fil.size() > 0) {
                    
                    
                    
                    ListView lop = new ListView();
                    for (int i = 0; i < fil.size(); i++) {
                        lop.getItems().add(fil.get(i));
                    }
                    
                    popup = new Popup();
                 
                    lop.setMaxHeight(80);
                    popup.getContent().addAll(lop);
                    popup.show(codeArea, codeArea.getCaretBounds().get().getMaxX(), codeArea.getCaretBounds().get().getMaxY());
                    codeArea.requestFocus();
                    
                }
                codeArea.requestFocus();
            }else { 
                if (popup != null) {
                    popup.hide();
                }
            }
        }
            
            
    });
于 2021-04-20T19:38:18.737 回答