我必须为电影开发一个网络应用程序。目前,在我的数据库中,我有一张用于人物和电影之间关系的表格,还有一张用于演员(也是人物)和电影之间关系的表格。最后一个还包含有关角色的信息。
我的问题根本不是规范化,我想知道在速度方面对每个表执行两个查询或将它们合并到一个具有 NULL 值的单个元组中的字符并执行单个查询是否更有效询问 ?
编辑:
目前的两个查询(图侧,获取他的演技和事业):
$query1 = '
SELECT RelationFigureCardType.department, RelationFigureCardType.job, Movie.card_type_id, Movie.id, Movie.original_name, Movie.release_date, Movie.cover, Movie.cover_ext
FROM relation_figure_cards AS RelationFigureCard
RIGHT JOIN relation_figure_card_types AS RelationFigureCardType ON
(RelationFigureCard.relation_figure_card_type_id = RelationFigureCardType.id)
RIGHT JOIN cards AS Movie ON
(RelationFigureCard.card_id = Movie.id)
WHERE
RelationFigureCard.figure_card_id = '.$figureId.'
AND RelationFigureCard.last_card_version = 1
ORDER BY Movie.card_type_id, RelationFigureCardType.priority, Movie.release_date
;
';
$query2 = '
SELECT RelationActorCard.is_main, RelationActorCard.is_guest, Movie.card_type_id, Movie.id, Movie.original_name, Movie.release_date, Movie.cover, Movie.cover_ext, Character.id, Character.original_name, Character.cover, Character.cover_ext
FROM relation_actor_cards AS RelationActorCard
RIGHT JOIN cards AS `Character` ON
(RelationActorCard.character_card_id = Character.id)
RIGHT JOIN cards AS Movie ON
(RelationActorCard.card_id = Movie.id)
WHERE
RelationActorCard.figure_card_id = '.$figureId.'
AND RelationActorCard.last_card_version = 1
ORDER BY Movie.card_type_id, Movie.release_date
;
';