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从未使用过 c++ 并遇到问题。我意识到我无法记录整个对象owner并查看其结构。在代码片段中，您可以看到 db 插入适用于硬编码字符串old_account_name。这个字符串只是一个硬编码的EOS公钥。我知道对象中应该有一个带有公钥的数组，owner但由于类型转换，我无法靠近他。请告诉我解决此问题并获取公钥字符串的正确方法。

 else if (action.name == N(newaccount)) {
                   auto new_account_name = abi_data["newact"].as<chain::name>().to_string();
                   auto creator = abi_data["creator"].as<chain::name>().to_string();
//hardcoded works  std::string old_account_name = "EOS7ea3Dj15nUkKz3diU7BmE5FV5aNKsBKL6TEST";
                   auto owner = abi_data["owner"].as<chain::authority>();
// doesn't work    std::string public_k1 = owner.keys[0].key.as<chain::authority>();
// doesn't work    std::string public_k2 = owner.keys[0].key.as<chain::public_key_type>();
    
                   ilog("new_account_name: " + new_account_name + " ,creator: " + creator);
    
                   *m_session << "UPDATE user_address SET address = :nan WHERE crypto_currency_asset_id = :ai AND address = :oan",
                      soci::use(new_account_name, "nan"),
                      soci::use(old_account_name, "oan"),
                      soci::use(asset_id, "ai");
                }

错误：no viable conversion from 'eosio::chain::public_key_type' (aka 'fc::crypto::public_key') to 'std::string'

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