2

如果有一个变量像

x = 80

或类似的数据框

进步
0 80

那么我如何创建一个如下图所示的图表
在此处输入图像描述

4

1 回答 1

3

您可以使用:

df = pd.DataFrame({'names' : ['progress',' '],
                   'values' :  [progress, 100 - progress]})

fig = px.pie(df, values ='values', names = 'names', hole = 0.5,
             color_discrete_sequence = ['FC0080', 'rgba(0,0,0,0)']
            )

并得到:

在此处输入图像描述

完整代码:

import plotly.express as px
import pandas as pd

# data
progress = 80
df = pd.DataFrame({'names' : ['progress',' '],
                   'values' :  [progress, 100 - progress]})

# plotly
fig = px.pie(df, values ='values', names = 'names', hole = 0.5,
             color_discrete_sequence = ['red', 'rgba(0,0,0,0)']
            )

fig.data[0].textfont.color = 'white'
# fig.show()
fig.show()

f = fig.full_figure_for_development(warn=False)
fig.show()
于 2021-04-12T19:41:38.897 回答