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我的代码有效，但想要一个更清洁的。我有 24 个 ON 和 OFF 按钮。单击 ON 按钮时，它将被禁用并变为绿色，而 OFF 按钮将变为灰色并显示“！禁用”。有没有办法做到这一点，而无需大量的 ON 和 OFF 方法？目前我有 48 种方法、样式等，总计 800 行代码。我知道必须有更好的方法...

这是一个例子：

from tkinter import *
from tkinter import ttk
class APP:
    def __init__(self, master):
        master.title('APP')
        master.resizable(False, False)

        self.style = ttk.Style()

        self.frame_header = ttk.Frame(master)
        self.frame_header.pack()

        self.frame_stations = ttk.Frame(master)
        self.frame_stations.pack()
        # default style and text of button
        self.style.configure('n1_on.TButton', foreground='#d2d2d2',font=('Arial', 15,'bold'))
        self.style.configure('n1_off.TButton', foreground='#d2d2d2', font=('Arial',15,'bold'))
        self.style.configure('n2_on.TButton',  foreground='#d2d2d2',font=('Arial', 15,'bold'))
        self.style.configure('n2_off.TButton', foreground='#d2d2d2', font=('Arial', 15,'bold'))
        # changes state (disabled) and font color when clocked
        self.style.map('n1_on.TButton', foreground=[('disabled','green')])
        self.style.map('n1_off.TButton', foreground=[('disabled','red')])
        self.style.map('n2_off.TButton', foreground=[('disabled','red')])
        self.style.map('n2_on.TButton', foreground=[('disabled','green')])

        ttk.Label(self.frame_stations, text="BUTTONS").grid(row=0, column=1, columnspan=2, padx=5)
        #buttons created adn location
        self.n1_on = ttk.Button(self.frame_stations, text='ON', style='n1_on.TButton', command=self.n1_on_state,)
        self.n1_on.grid(row=1, column=1)
        self.n2_on = ttk.Button(self.frame_stations, text='ON', style='n2_on.TButton', command=self.n2_on_state)
        self.n2_on.grid(row=2, column=1)

        self.n1_off = ttk.Button(self.frame_stations, text='OFF', style= 'n1_off.TButton', command=self.n1_off_state)
        self.n1_off.grid(row=1, column=2)
        self.n2_off= ttk.Button(self.frame_stations, text='OFF', style='n2_off.TButton', command=self.n2_off_state)
        self.n2_off.grid(row=2, column=2)

    def n1_on_state(self):
        print('n1 turned on')
        self.n1_on.state(['disabled'])
        self.n1_off.state(['!disabled'])

    def n2_on_state(self):
        print('n2 turned on')
        self.n2_on.state(['disabled'])
        self.n2_off.state(['!disabled'])

    def n1_off_state(self):
        print('n1_turned off')
        self.n1_on.state(['!disabled'])
        self.n1_off.state(['disabled'])

    def n2_off_state(self):
        print('n2 turned off')
        self.n2_on.state(['!disabled'])
        self.n2_off.state(['disabled'])
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1 回答 1

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你就不能这样定义吗？为什么每次都要为每个按钮定义函数？

# Define this above your code and pass it the buttons you want to turn on or off
def turn_off_buttons(turn_off, turn_on):
    # Also when we want to inform the user we usually put the 'print' statement after the work is finished 
    # print(f'{turn_off} turned off') (Not here)
    # turn_on.state(['!disabled']) 
    # turn_off.state(['disabled'])
    # I would suggest you to use 'config' instead of state since it is more applicable
    turn_off.config(state=DISABLED)
    turn_on.config(state=NORMAL)
    print(f'{turn_off} turned off')

例子：

from tkinter import *
from tkinter import ttk


# Define this above your code and pass it the buttons you want to turn on or off
def turn_off_buttons(turn_off, turn_on):
    # Also when we want to inform the user we usually put the 'print' statement after the work is finished 
    # print(f'{turn_off} turned off') (Not here)
    # turn_on.state(['!disabled']) 
    # turn_off.state(['disabled'])
    # I would suggest you to use 'config' instead of state since it is more applicable
    turn_off.config(state=DISABLED)
    turn_on.config(state=NORMAL)
    print(f'{turn_off} turned off')

class TurnOnOff:
    def __init__(self):
        self.root = Tk()
        self.root.geometry("550x280")
        self.button1 = ttk.Button(self.root, text="Turn On", command=lambda: turn_off_buttons(self.button1, self.button2))
        self.button2 = ttk.Button(self.root, text="Turn Off", command=lambda: turn_off_buttons(self.button2, self.button1))
        self.button1.pack(pady=5)
        self.button2.pack(pady=5)
        self.root.mainloop()


if __name__ == "__main__":
    TurnOnOff()
于 2021-04-10T14:47:48.207 回答