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我对 Hibernate 和 CrudRepository 有疑问。

我有一个控制器，它返回一组由视图获取的结果。我创建了一个视图，因为我认为这是管理我的数据库实体的最佳方式，它是这样创建的：

CREATE TABLE Characters (
  CHARACTER_ID INT ,
  CHARACTER_NAME VARCHAR(50) NOT NULL,
  CHARACTER_ICON VARCHAR(250) NOT NULL,
  gender VARCHAR(10) NOT NULL,
  status VARCHAR(15) NOT NULL,
  clevel INT NOT NULL,
  experience INT NOT NULL,
  TOTAL_EXPERIENCE INT NOT NULL,
  health INT NOT NULL,
  HEALTH_STATUS VARCHAR(20) NOT NULL,
  role VARCHAR(20) NOT NULL,
  PRIMARY KEY (CHARACTER_ID)
);

CREATE TABLE GUILDROLE (
ROLE_ID INT NOT NULL,
GUILD_ID INT NOT NULL,
NAME VARCHAR(50) NOT NULL,
SALARY INT NOT NULL,
MANAGER BIT NOT NULL,
ROLE_IMG VARCHAR(250),
DESCRIPTION VARCHAR(800),
GUILD_LEVEL INT NOT NULL,
PRIMARY KEY (ROLE_ID,GUILD_ID)
);

CREATE TABLE GUILDMEMBER (
CHARACTER_ID INT NOT NULL,
ROLE_ID INT NOT NULL,
PRIMARY KEY(CHARACTER_ID,ROLE_ID)
);

CREATE VIEW V_GUILDMEMBERS
AS
SELECT
 GR.GUILD_ID AS GUILD_ID,
 GR.ROLE_ID AS ROLE_ID,
 CH.CHARACTER_ID AS CHARACTER_ID,
 CH.CHARACTER_NAME AS CHARACTER_NAME,
 GR.GUILD_LEVEL AS GUILD_LEVEL,
 GR.NAME AS ROLE_NAME,
 GR.ROLE_IMG AS ROLE_IMG
FROM GUILDMEMBER GM
 JOIN GUILDROLE GR
ON GM.ROLE_ID = GR.ROLE_ID
 JOIN CHARACTERS AS CH
ON CH.CHARACTER_ID = GM.CHARACTER_ID;

我已经实现了像这样对 View 建模的类：

import lombok.Data;
import org.hibernate.annotations.Immutable;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Immutable
@Data
public class V_GuildMembers {

    @Id
    @Column(name = "GUILD_ID")
    private Integer guildId;

    @Column(name = "ROLE_ID")
    private Integer roleId;

    @Column(name = "CHARACTER_ID")
    private Integer characterId;

    @Column(name = "CHARACTER_NAME")
    private String characterName;

    @Column(name = "GUILD_LEVEL")
    private Integer guildLevel;

    @Column(name = "ROLE_NAME")
    private String roleName;

    @Column(name = "ROLE_IMG")
    private String roleImg;

}

我的 RepositoryService 看起来像这样：

public List<V_GuildMembers> getGuildMembers(Integer guildId){
        List<V_GuildMembers> members = new ArrayList<>();
        if(guildId != null){
            members = guildMemberListRepository.findMembersByGuildId(guildId);
        }
        return members;
    }

最后，我有这样的存储库界面：

import com.novavrbe.vrbe.dto.V_GuildMembers;
import org.springframework.data.jpa.repository.JpaSpecificationExecutor;
import org.springframework.data.repository.CrudRepository;

import java.util.List;
import java.util.Optional;

public interface GuildMemberListRepository extends CrudRepository<V_GuildMembers, Integer>, JpaSpecificationExecutor<V_GuildMembers> {

    default List<V_GuildMembers> findMembersByGuildId(Integer guildId) {
        return findAll(
                (root, query, criteriaBuilder)-> criteriaBuilder.equal(root.get("guildId"), guildId)
        );

    }

    default Optional<V_GuildMembers> getGuildMemberbyID(Integer characterid){

        return findOne(((root, criteriaQuery, criteriaBuilder) -> criteriaBuilder.equal(root.get("characterId"),characterid)));

    }
}

在不使用 CrudRepository 和在 Sql Manager 或 MySql Workbench 上使用普通 Select 的情况下，一切都可以完美运行。我在同一个 Giuld 中添加了 3 个公会成员，具有不同的名称和角色，但是我从控制器和方法 findMembersByGuildId(guildId) 获得的结果集如下：

"members": [
        {
            "role_ID": 5,
            "character_ID": 1,
            "guild_LEVEL": 50,
            "guild_ID": 1,
            "role_IMG": "",
            "character_NAME": "Marzio Paparzio",
            "role_NAME": "Legatus"
        },
        {
            "role_ID": 5,
            "character_ID": 1,
            "guild_LEVEL": 50,
            "guild_ID": 1,
            "role_IMG": "",
            "character_NAME": "Marzio Paparzio",
            "role_NAME": "Legatus"
        },
        {
            "role_ID": 5,
            "character_ID": 1,
            "guild_LEVEL": 50,
            "guild_ID": 1,
            "role_IMG": "",
            "character_NAME": "Marzio Paparzio",
            "role_NAME": "Legatus"
        }
    ]

事实上，结果似乎复制了其中一个记录结果的确切时间。我希望有人能给我帮助！

提前致谢

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0 回答 0