python - 在 Python 中将 IPv4 范围（开始和结束）转换为斜线表示法？

Question

是否有可用于将起始和结束 IP 地址转换为斜线符号的脚本？

例子：

>>> ip_long = '10.182.71.0-10.182.75.255'
>>> convert_to_slash(ip_long)
10.182.71.0/24, 10.182.72.0/22

Answer 1

使用summarize_address_range()from ipaddress，它是 Python 3 标准库的一部分（并且向后移植到 Python 2）。

>>> import ipaddress
>>> first = ipaddress.IPv4Address('10.182.71.0')
>>> last = ipaddress.IPv4Address('10.182.75.255')
>>> summary = ipaddress.summarize_address_range(first, last)
>>> list(summary)
[IPv4Network('10.182.71.0/24'), IPv4Network('10.182.72.0/22')]

Answer 2

Google 的 ipaddr-py 库有一个名为 summarise_address_range(first, last) 的方法。

summarize_address_range(first, last):
"""Summarize a network range given the first and last IP addresses.

Example:
    >>> summarize_address_range(IPv4Address('1.1.1.0'),
        IPv4Address('1.1.1.130'))
    [IPv4Network('1.1.1.0/25'), IPv4Network('1.1.1.128/31'),
    IPv4Network('1.1.1.130/32')]

Args:
    first: the first IPv4Address or IPv6Address in the range.
    last: the last IPv4Address or IPv6Address in the range.

Returns:
    The address range collapsed to a list of IPv4Network's or
    IPv6Network's.

Raise:
    TypeError:
        If the first and last objects are not IP addresses.
        If the first and last objects are not the same version.
    ValueError:
        If the last object is not greater than the first.
        If the version is not 4 or 6.
"""

Answer 3

另一种解决方案：

from ipaddress import IPv4Address, summarize_address_range

a=" ".join(map(str, summarize_address_range(IPv4Address('8.8.8.8'), IPv4Address('8.8.9.1'))))

print(a)