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如何将函数结果分配给 WITH 子句中的名称?
试过:
with has_perm as ( has_perm(:user) ) select * from my_table where has_perm = 'Y'
这是你想要的吗?
with has_perm as ( select has_perm(:user) as has_perm from dual ) select * from my_table where 'Y' = (select has_perm from has_perm);
为什么不在没有 CTE 的情况下写这个?
select * from my_table where has_perm(:user) = 'Y';