1

我正在使用 simple_salesforce 来获取对象的所有字段名称的列表。

我有以下

from simple_salesforce import Salesforce

sf = Salesforce(username = username, password = pass....) #Connecting to sf

#I'm using salesforce object api names to get all the fields that belong to that object
Api_names = ["Account", "Contact", "Campaign"]

desc = {}
for obj in Api_names:
    if obj == "Account":
        desc = sf.Account.describe()
    elif obj == "Contact":
        desc = sf.Contact.describe()
    elif obj == "Campaign":
        desc = sf.Campaign.describe()

    field_names_list_1 = [field['name'] for field in desc['fields']]

    #do something with the list... for now, I'm just adding break
    break

我想写这样的东西

Api_names = ["Account", "Contact", "Campaign"]
for obj in Api_names:
    desc = sf.obj.describe()

但它将 obj 视为 api 名称。我确实尝试了soql方式

query = sf.query("SELECT QualifiedApiName FROM FieldDefinition WHERE
EntityDefinition.QualifiedApiName IN ('{0}')".format("Account"))

field_names_list_2 = []
for i in range(0, query['totalSize']):
    field_names_list_2.append(query['records'][i]["QualifiedApiName"])

但是,对于 Account 对象,field_names_list_1并且field_names_list_2有不同的长度。field_names_list_1 包含所有字段,但 field_names_list_2 缺少一些字段。不知道为什么。

我可以更改什么,sf.obj.describe()以便将 obj 视为实际变量而不是 salesforce 对象名称?

4

1 回答 1

1

用于getattr()动态获取对象代理simple_salesforce

api_names = ["Account", "Contact", "Campaign"]
for obj in Api_names:
    desc = getattr(sf, obj).describe()
于 2021-04-01T22:26:42.440 回答