由于您只需要知道月级别的重叠而不是日级别的重叠,因此您可以认为经理从第 1 天开始并在月的最后一天离开。这可以使用floor_date
和ceiling_date
from package来实现lubridate
。
library(lubridate)
w.extended <- w
w.extended$start.date <- floor_date(as.Date(w.extended$start.date), "month")
w.extended$end.date <- ceiling_date(as.Date(w.extended$end.date), "month") - 1
#List of months
timeperiod <- seq(min(w.extended$start.date),
by = "month",
to = max(w.extended$end.date))
然后,您可以a %within% b
从包中使用lubridate
它可以检查日期是否在间隔列表内。使用您提供的间隔将此功能应用于您的每个月。
df <- data.frame(t(sapply(timeperiod,
function(x){
managersWorking <- x %within% interval(w.extended$start.date,
w.extended$end.date)
c(as.character(x), managersWorking)
})),
stringsAsFactors = F)
#Replace the 'character' format of columns to the appropriate one
df[-1] <- apply(df[-1], 2, as.logical)
df[,1]<- format(as.Date(df[,1]), "%Y/%m")
colnames(df) <- c("month", paste0("manager.", w$manager))
head(df)
# month manager.a manager.b manager.c manager.d manager.e manager.f
#1 1999/09 FALSE FALSE TRUE FALSE FALSE FALSE
#2 1999/10 FALSE FALSE TRUE FALSE FALSE FALSE
#3 1999/11 FALSE FALSE TRUE FALSE FALSE FALSE
#4 1999/12 FALSE FALSE TRUE FALSE FALSE FALSE
#5 2000/01 FALSE FALSE TRUE FALSE FALSE FALSE
#6 2000/02 FALSE FALSE TRUE FALSE FALSE FALSE
原始数据:
w <- read.table(header=TRUE, text="
start.date end.date manager
2006-05-01 2007-04-30 a
2006-09-30 2007-12-31 b
1999-09-30 2007-12-31 c
2008-01-01 2012-04-30 d
2008-01-01 2020-02-28 e
2009-05-01 2016-04-08 f")
w
# start.date end.date manager
#1 2006-05-01 2007-04-30 a
#2 2006-09-30 2007-12-31 b
#3 1999-09-30 2007-12-31 c
#4 2008-01-01 2012-04-30 d
#5 2008-01-01 2020-02-28 e
#6 2009-05-01 2016-04-08 f