我的一些功能需要UniversalXPConnect
启用权限。
netscape.security.PrivilegeManager.enablePrivilege('UniversalXPConnect');
因此,我的函数如下所示:
function oneOfMyFunctions() {
netscape.security.PrivilegeManager.enablePrivilege('UniversalXPConnect');
// ...
}
实际上,当特权被拒绝时,我也try
例外catch
。如下所示:
try {
netscape.security.PrivilegeManager.enablePrivilege('UniversalXPConnect');
// ...
} catch (e) {
// ...
}
我宁愿把它作为一个单独的函数,并从我的函数中调用它,如下所示:
function oneOfMyFunctions() {
if (enablePrivilege()) {
// ...
} else {
// ...
}
}
假设enablePrivilege
函数如下:
function enablePrivilege() {
try {
netscape.security.PrivilegeManager.enablePrivilege('UniversalXPConnect');
} catch (e) {
return false;
}
return true;
}
但是,出于安全原因,这是不可能的,因为特权仅在请求功能的范围内被授予。
那么,唯一的选择是将该代码块包含在我的每个函数中吗?
更新:
正如我还将try
讨论catch
其他一些例外情况,我最终得到了以下设计:
function readFile(path, start, length) {
netscape.security.PrivilegeManager.enablePrivilege('UniversalXPConnect');
var file = Components.classes['@mozilla.org/file/local;1'].createInstance(Components.interfaces.nsILocalFile);
file.initWithPath(path);
var istream = Components.classes['@mozilla.org/network/file-input-stream;1'].createInstance(Components.interfaces.nsIFileInputStream);
istream.init(file, -1, -1, false);
istream.QueryInterface(Components.interfaces.nsISeekableStream);
istream.seek(0, start);
var bstream = Components.classes['@mozilla.org/binaryinputstream;1'].createInstance(Components.interfaces.nsIBinaryInputStream);
bstream.setInputStream(istream);
return bstream.readBytes(length);
}
var filepath = 'C:\\test.txt', start = 440, length = 5;
try {
console.log(readFile(filepath, start, length));
} catch (e) {
if (e.name == 'Error') console.log('The privilege to read the file is not granted.');
else console.log('An error happened trying to read the file.');
}