serialization - 使用fastJson时如何使用@type反序列化Json字符串以级联对象图

Question

我有一个 JSon 字符串，我想将它恢复为 Java 对象，其类具有相同的父类。我期望的是创建一些 class 对象AbsNode，并设置参考图。

我试过的：

    //Object node = JSON.parseObject(json, AbsNode.class, Feature.IgnoreAutoType); //node=null
       Object node = JSON.parse(json, Feature.IgnoreAutoType); //node is  aJsonObject, not AbsNode

    System.out.println(node.toString());

但这些都不符合我的要求。那么，使用 FastJson 实现我的目标的正确方法是什么？

Json 字符串是：

{
   "@type":".GuardNode",
   "worker":{
      "@type":"AI.DirectNode",
      "key":"worker1",
      "val":1
   },
   "fallback":{
      "@type":"AI.GuardNode",
      "worker":{
         "@type":"AI.DirectNode",
         "key":"worker2",
         "val":2
      },
      "fallback":{
         "@type":"AI.GuardNode",
         "worker":{
            "@type":"AI.DirectNode",
            "key":"worker3",
            "val":3
         },
         "fallback":{
            "@type":"AI.GuardNode",
            "worker":{
               "@type":"AI.DirectNode",
               "key":"worker4",
               "val":4
            },
            "fallback":{
               "@type":"AI.DirectNode",
               "key":"worker5",
               "val":5
            }
         }
      }
   }
}

和课程：

public abstract class AbsNode {

    public abstract NodeResult execute();
}
@AllArgsConstructor
@Data
public class DirectNode extends AbsNode {
    @JSONField(name = "key")
    String key;

    @JSONField(name = "val")
    int val;
}
@AllArgsConstructor
@Data
public class GuardNode extends AbsNode {
    @JSONField(name = "worker")
    AbsNode worker;

    @JSONField(name = "fallback")
    AbsNode fallback;
}
@AllArgsConstructor
@Data
public class ParallelNode<T> extends AbsNode {

    @JSONField(name = "workers")
    List<AbsNode> workers;

    @JSONField(name = "weights")
    List<Double> weights;
}

生成Graph的源代码：

 DirectNode worker1 = new DirectNode("worker1", 1);
        DirectNode worker2 = new DirectNode("worker2", 2);
        DirectNode worker3 = new DirectNode("worker3", 3);
        DirectNode worker4 = new DirectNode("worker4", 4);
        DirectNode worker5 = new DirectNode("worker5", 5);

        AbsNode l1 = new GuardNode(worker4, worker5);
        AbsNode l2 = new GuardNode(worker3, l1);
        AbsNode l3 = new GuardNode(worker2, l2);
        AbsNode root = new GuardNode(worker1, l3);

        String json =
            JSON.toJSONString(root, SerializerFeature.WRITE_MAP_NULL_FEATURES, SerializerFeature.WriteClassName);