我正在学习 Java,并遇到了构造函数链接的概念。所以我写了一个简单的程序来演示。有两个类-父类(SuperClass)和扩展父类的子类(ChildClass)。
public class SuperClass {
int x;
SuperClass(){
this(10);
System.out.println("No arg SuperClass Constructor");
}
SuperClass(int x){
this.x = x;
System.out.println("1 arg SuperClass Constructor" + this.x);
}
}
public class ChildClass extends SuperClass{
ChildClass(){
this(10);
System.out.println("No arg ChildClass Constructor");
}
ChildClass(int x){
System.out.println("1 arg ChildClass Constructor" + x);
}
public static void main(String[] args) {
ChildClass c = new ChildClass();
}
}
所以我得到了这个输出:
1 arg SuperClass Constructor10
No arg SuperClass Constructor
1 arg ChildClass Constructor10
No arg ChildClass Constructor
我只是稍微调整了我的代码,因为我想使用 super 关键字,我尝试了下面的代码。
public class SuperClass {
int x;
SuperClass(){
this(10);
System.out.println("No arg SuperClass Constructor");
}
SuperClass(int x){
this.x = x;
System.out.println("1 arg SuperClass Constructor" + this.x);
}
}
public class ChildClass extends SuperClass{
ChildClass(){
this(10);
System.out.println("No arg ChildClass Constructor");
}
ChildClass(int x){
super(x); //Here added a super method
System.out.println("1 arg ChildClass Constructor" + this.x);
}
public static void main(String[] args) {
ChildClass c = new ChildClass();
}
}
现在我得到如下输出,
1 arg SuperClass Constructor10
1 arg ChildClass Constructor10
No arg ChildClass Constructor
为什么我super()
在第二个程序中使用时没有调用父级的默认构造函数?