python - Pydroid 能识别 random.choice 吗？

Question

这是我的代码

user_action = input("enter rock, paper, or scissors:  ")
possible_action = ["rock", "paper", "scissors"]
computer_action = random.choice(possible_action)

它告诉我这是一个无效的变量。

我做错了什么还是Pydroid的错？

Answer 1

唯一可能的问题是您忘记了

随机导入

这段代码工作得很好：

import random
user_action = input("enter rock, paper, or scissors:  ")
possible_action = ["rock", "paper", "scissors"]
computer_action = random.choice(possible_action)
print(computer_action)