python-3.x - 树形图 - 更改字体

Question

所以我有以下代码在 Matplotlib 中生成树形图。想知道是否有可能让第一行加粗和更大的字体大小。

所以：

大胆和更大：0：

更小且无底气：480

    import matplotlib.pyplot as plt
    import squarify    # pip install squarify (algorithm for treemap)
    import pandas as pd
    import psycopg2
    distributionlist = [480, 104, 55, 35, 29, 12, 18, 22, 14, 11, 144]
    group = ["0", "1", "2", "3", "4", "5", "6", "7","8","9","10+"]

    labels = ["%s:\n%s" % (label) for label in zip(group, distributionlist)]



    percents = [8,3,4,2,8,3,4,2]
    # Create a data frame with fake data
    df = pd.DataFrame({'nb_people': distributionlist, 'group':group })
    #df = pd.DataFrame({'nb_people':[8,3,4,2], 'group':["group A", "group B", "group C", "group D"] })

    # plot it

    squarify.plot(sizes=df['nb_people'], label=labels, alpha=.8)

    #squarify.plot(sizes=df['nb_people'], label=df['group'], alpha=.8 , color=colors )
    plt.axis('off')
    plt.show()

Answer 1

通常单个 matplotlib 文本只有一种尺寸和一种样式。在这里，标签被创建为一个带有换行符的字符串。

您可以使用

ax = squarify.plot(sizes=df['nb_people'], label=labels, alpha=.8)
ax.texts[0].set_size(30)
ax.texts[0].set_weight('bold')

将文本设置为更大和粗体。

要拆分文本并仅设置第一行的权重：

ax = squarify.plot(sizes=df['nb_people'], label=labels, alpha=.8)
text_parts = ax.texts[0].get_text().split("\n")
ax.texts[0].set_text(text_parts[0] + "\n")
ax.texts[0].set_size(30)
x, y = ax.texts[0].get_position()
new_text = ax.text(x, y, "\n" + text_parts[1], ha=ax.texts[0].get_ha(), va=ax.texts[0].get_va())
new_text.set_fontproperties(ax.texts[0].get_fontproperties())
ax.texts[0].set_weight('bold')