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我有以下 XML 数据，并希望在 KS 中获取数据，如下所示：

<DW>
  <KS>
    <KeyInfo Name="IlluSetting">
      <KeyTypeValue>Text</KeyTypeValue>
      <ValueString>yDipol90</ValueString>
    </KeyInfo>
     <KeyInfo Name="IlluSetting2">
      <KeyTypeValue>Text</KeyTypeValue>
      <ValueString>yDipol</ValueString>
    </KeyInfo>
  </KS>
  <MDESC>Tx [mrad]</MDESC>
   <MNUMBER>0.12102</MNUMBER>
</DW>
<DW>
  <KS>
    <KeyInfo Name="IlluSetting3">
      <KeyTypeValue>Text</KeyTypeValue>
      <ValueString>yDipol80</ValueString>
    </KeyInfo>
  </KS>
  <MDESC>Ty [mrad]</MDESC>
  <MNUMBER>0.12102</MNUMBER>
</DW>

有没有办法获得具有以下输出的表：

Name            ValueString     Name            ValueString
-----------------------------------------------------------
IlluSetting     yDipol90        IlluSetting2    yDipol
IlluSetting3    yDipol80

意思就是里面的数据<KS>... </KS>会连续显示

非常感谢

4

1 回答 1

0

请尝试以下解决方案。我们在这里所做的称为切碎，即将XML 转换为矩形/关系格式。

因为没有提供DDL 和样本数据总体，所以我从臀部射击。

由于缺少根元素，提供的 XML 格式不正确，但 SQL Server 允许处理 XML 片段。

.nodes()我们正在使用XQuery及其.value()方法。

SQL，方法 #1

-- DDL and sample data population, start
DECLARE @xml XML =
N'<DW>
    <KS>
        <KeyInfo Name="IlluSetting">
            <KeyTypeValue>Text</KeyTypeValue>
            <ValueString>yDipol90</ValueString>
        </KeyInfo>
        <KeyInfo Name="IlluSetting2">
            <KeyTypeValue>Text</KeyTypeValue>
            <ValueString>yDipol</ValueString>
        </KeyInfo>
    </KS>
    <MDESC>Tx [mrad]</MDESC>
    <MNUMBER>0.12102</MNUMBER>
</DW>
<DW>
    <KS>
        <KeyInfo Name="IlluSetting3">
            <KeyTypeValue>Text</KeyTypeValue>
            <ValueString>yDipol80</ValueString>
        </KeyInfo>
    </KS>
    <MDESC>Ty [mrad]</MDESC>
    <MNUMBER>0.12102</MNUMBER>
</DW>';
-- DDL and sample data population, end

SELECT c.value('KeyInfo[1]/@Name', 'VARCHAR(30)') AS name1
    , c.value('(KeyInfo[1]/ValueString/text())[1]', 'VARCHAR(30)') AS ValueString1
    , COALESCE(c.value('KeyInfo[2]/@Name', 'VARCHAR(30)'), '') AS name2
    , COALESCE(c.value('(KeyInfo[2]/ValueString/text())[1]', 'VARCHAR(30)'), '') AS ValueString2
FROM @xml.nodes('/DW/KS') AS t(c);

输出

+--------------+--------------+--------------+--------------+
|    name1     | ValueString1 |    name2     | ValueString2 |
+--------------+--------------+--------------+--------------+
| IlluSetting  | yDipol90     | IlluSetting2 | yDipol       |
| IlluSetting3 | yDipol80     |              |              |
+--------------+--------------+--------------+--------------+

SQL，方法 #2

DECLARE @CrLf CHAR(2) = CHAR(13) + CHAR(10)
   , @tokenCounter INT
   , @i INT = 1;

-- Calculate max number of tokens in the <KS>
SET @tokenCounter = (SELECT MAX(c.value('count(KeyInfo)', 'INT'))
FROM @xml.nodes('/DW/KS') AS t(c));

DECLARE @SQL NVARCHAR(MAX) = 'SELECT ';

WHILE @i <= @tokenCounter BEGIN
    SET @SQL += IIF(@i>1,', ','') + 'COALESCE(c.value(''KeyInfo[' + CAST(@i AS VARCHAR(3)) + ']/@Name'', ''VARCHAR(30)''), '''') AS NAME' + CAST(@i AS VARCHAR(3)) + @CrLf
    SET @SQL += ', COALESCE(c.value(''(KeyInfo[' + CAST(@i AS VARCHAR(3)) + ']/ValueString/text())[1]'', ''VARCHAR(30)''), '''') AS ValueString' + CAST(@i AS VARCHAR(3)) + @CrLf

    SET @i += 1
END

SET @SQL += 'FROM @xml.nodes(''/DW/KS'') AS t(c);';

-- just to see it
PRINT @sql;

-- we are ready at this point
EXEC sp_executesql @stmt = @SQL, @params = N'@xml xml', @xml = @xml;
于 2021-03-18T21:38:04.150 回答