30

如何从 仅获取Internet 协议版本 4地址Dns.GetHostAddresses()？我有下面的代码，它给了我 IPv4 和 IPv6 地址。我必须让它与具有多个 IPv4 地址的盒子一起工作。

IPAddress[] localIPs = Dns.GetHostAddresses(Dns.GetHostName());
private void get_IPs()
    {
        foreach (IPAddress a in localIPs)
        {
           server_ip = server_ip + a.ToString() + "/";
        }
    }
4

11 回答 11

36

从我的博客：

/// <summary> 
/// This utility function displays all the IP (v4, not v6) addresses of the local computer. 
/// </summary> 
public static void DisplayIPAddresses() 
{ 
    StringBuilder sb = new StringBuilder(); 

    // Get a list of all network interfaces (usually one per network card, dialup, and VPN connection) 
    NetworkInterface[] networkInterfaces = NetworkInterface.GetAllNetworkInterfaces(); 

    foreach (NetworkInterface network in networkInterfaces) 
    { 
        // Read the IP configuration for each network 
        IPInterfaceProperties properties = network.GetIPProperties(); 

        // Each network interface may have multiple IP addresses 
        foreach (IPAddressInformation address in properties.UnicastAddresses) 
        { 
            // We're only interested in IPv4 addresses for now 
            if (address.Address.AddressFamily != AddressFamily.InterNetwork) 
                continue; 

            // Ignore loopback addresses (e.g., 127.0.0.1) 
            if (IPAddress.IsLoopback(address.Address)) 
                continue; 

            sb.AppendLine(address.Address.ToString() + " (" + network.Name + ")"); 
        } 
    } 

    MessageBox.Show(sb.ToString()); 
}

特别是，我不推荐Dns.GetHostAddresses(Dns.GetHostName());，无论该行在各种文章和博客上有多受欢迎。

于 2011-07-12T18:05:58.460 回答
28

在您的代码中添加类似的内容

  if( IPAddress.Parse(a).AddressFamily == AddressFamily.InterNetwork )
  // IPv4 address
于 2011-07-12T18:01:23.190 回答
12

这是我使用的一个功能：

public static string GetIP4Address()
{
    string IP4Address = String.Empty;

    foreach (IPAddress IPA in Dns.GetHostAddresses(Dns.GetHostName()))
    {
        if (IPA.AddressFamily == AddressFamily.InterNetwork)
        {
            IP4Address = IPA.ToString();
            break;
        }
    }

    return IP4Address;
}

作为一个可枚举的：

public static IEnumerable<string> GetIP4Addresses()
{
    return Dns.GetHostAddresses(Dns.GetHostName())
        .Where(IPA => IPA.AddressFamily == AddressFamily.InterNetwork)
        .Select(x => x.ToString());
}
于 2011-07-12T18:01:42.197 回答
7

使用 Linq 时非常干净和甜美

IPAddress[] addresses = Dns.GetHostAddresses(Dns.GetHostName()).Where(a => a.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork).ToArray();
于 2013-12-05T02:16:34.347 回答
4

写locaIPs.Where(ip => ip.AddressFamily == AddressFamily.InterNetwork)

于 2011-07-12T18:00:54.127 回答
4

从MSDN 上的 Dns.GetHostAddresses，

当传递一个空字符串作为主机名时，此方法返回除 Windows Server 2003 之外的所有操作系统的本地主机的 IPv4 地址；对于 Windows Server 2003，将返回本地主机的 IPv4 和 IPv6 地址。

如果本地计算机没有安装 IPv6，则从 GetHostAddresses 方法的结果中过滤 IPv6 地址。因此，如果只有 IPv6 结果可用于 hostNameOrAddress.parameter，则可以取回一个空的 IPAddress 实例。

因此，您可以使用它来尝试解析它：

IPAddress.TryParse

然后检查AddressFamily哪个

返回 System.Net.Sockets.AddressFamily.InterNetwork 用于 IPv4 或 System.Net.Sockets.AddressFamily.InterNetworkV6 用于 IPv6。

string input = "192.168.0.10";

IPAddress address;
if (IPAddress.TryParse(input, out address))
{
    switch (address.AddressFamily)
    {
        case System.Net.Sockets.AddressFamily.InterNetwork:
            // we have IPv4
            break;
        case System.Net.Sockets.AddressFamily.InterNetworkV6:
            // we have IPv6
            break;
        default:
            // do something else
            break;
    }
}
于 2011-07-12T18:05:45.277 回答
1

我使用了开头的答案

/// <summary> and it mostly worked:
//for some reason Visual Studio 2010 did not understand AddressFamily.Inernetwork
    if (address.Address.AddressFamily != AddressFamily.InterNetwork)

我不得不使用：

if(address.Address.AddressFamily != System.Net.Sockets.AddressFamily.InterNetwork)

但我实际上用过：

if(!address.Address.AddressFamily.Equals(System.Net.Sockets.AddressFamily.InterNetwork))

另外，我补充说：

if (network.OperationalStatus != OperationalStatus.Up)
                continue;

因为有些网络无法正常工作而且不应该存在，所以我确实看到它们在注册表中。---阿尔文

于 2014-05-06T03:09:14.833 回答
0

对我来说，更清洁的解决方案是：

 public static string GetLocalIP() 
        {
            string ipv4Address = String.Empty;

            foreach (IPAddress currentIPAddress in Dns.GetHostAddresses(Dns.GetHostName()))
            {
                if (currentIPAddress.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
                {
                    ipv4Address = currentIPAddress.ToString();
                    break;
                }
            }

            return ipv4Address;
        }
于 2012-08-30T11:04:57.990 回答
0

我使用这个帮助方法，它在过滤掉 IPV6 和 Loopback 一次后返回第一个活动的 IPV4 地址


    public static IPAddress GetLocalIPAddress()
    {
        IPAddress result = null;
        IPHostEntry iphostentry = Dns.GetHostEntry(Dns.GetHostName());
        IPAddress[] ipv4Address = Array.FindAll(iphostentry.AddressList, add => add.AddressFamily == AddressFamily.InterNetwork && !IPAddress.IsLoopback(add));
        if (ipv4Address.Length > 0 )
        {
            result =ipv4Address[0];
        }
        return result;
    }
于 2014-02-11T23:15:57.107 回答
0

这是我的代码。并且可以在许多 LAN 卡上找到它。

private string GetLocalIpAddress()
{
    string localIpAddress = string.Empty;
    NetworkInterface[] nics = NetworkInterface.GetAllNetworkInterfaces();

    foreach (NetworkInterface nic in nics)
    {
        if (nic.OperationalStatus != OperationalStatus.Up)
        {
            continue;
        }

        IPv4InterfaceStatistics adapterStat = (nic).GetIPv4Statistics();
        UnicastIPAddressInformationCollection uniCast = (nic).GetIPProperties().UnicastAddresses;

        if (uniCast != null)
        {
            foreach (UnicastIPAddressInformation uni in uniCast)
            {
                if (adapterStat.UnicastPacketsReceived > 0
                    && adapterStat.UnicastPacketsSent > 0
                    && nic.NetworkInterfaceType != NetworkInterfaceType.Loopback)
                {
                    if (uni.Address.AddressFamily == AddressFamily.InterNetwork)
                    {
                        localIpAddress = nic.GetIPProperties().UnicastAddresses[0].Address.ToString();

                        break;
                    }
                }
            }
        }
    }

    return localIpAddress;
}
于 2017-11-08T09:26:05.920 回答
0

这是使用 for 循环查找第一个连接的 IPv4 的代码：

        IPAddress ipAddress = null;
        IPAddress[] localIPs = Dns.GetHostAddresses(Dns.GetHostName());           

        for (int i=0 ; i<localIPs.Length ; i++)
        {
            if (localIPs[i].AddressFamily == AddressFamily.InterNetwork)
            {
                ipAddress = localIPs[i];
                break;
            }                
        }
于 2019-02-13T21:30:09.997 回答