php - 使用 PHP-DI 和 PHPUnit 模拟某个构造函数参数

Question

我正在使用 PHP-DI 将类注入到构造函数中，如下所示

class StravaWebhookService extends ApplicationService
{
    private ContainerInterface $container;
    private UserService $userService;
    private ActivityService $activityService;

    public function __construct(
        ContainerInterface $container,
        UserService $userService,
        ActivityService $activityService,
    )
    {
        $this->container = $container;
        $this->userService = $userService;
        $this->activityService = $activityService;
    }

   
    public function activityCreate($activityId, $ownerId): void
    {
        $activity = $this->activityService->findByActivityId($activityId); // <--- want to mock this so I can return a predefined value in a test
    }
}

现在我想知道是否可以用一个模拟替换我的构造函数中的一个参数，这样我就可以定义一个要返回的值，$this->activityService->findByActivityId($activityId);而不是调用那个真正的类。

我试过了

1. 使用 mockbuilder，问题是我必须模拟每个构造函数注入的类

        $stravaWebhookService = $this->getMockBuilder(StravaWebhookService::class)
            ->setConstructorArgs([
                $containerStub, //<----- have to mock or create this too
                $activityServiceStub,
                $stravaServiceStub, //<----- have to mock or create this too
            ])
            ->getMock();