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我有一个学者列表，用于解析他们可用的 Google 学者 ID。不知何故，我得到了“下标越界”的错误，但我无法与此问题提供的其他响应相关联。代码如下。谢谢！：

library(scholar)
    for (i in 1:200){
  
  scholars<-get_scholar_id(last_name = list$Last.Name[i], 
                 first_name = list$First.Name[i],
                 affiliation = "ABC University")
}

这导致：

No Scholar ID found.
No Scholar ID found.
Error in tables[[1]] : subscript out of bound

但是，如果我确实提出：

  scholars_B<-get_scholar_id(last_name = list$Last.Name[3], 
                 first_name = list$First.Name[3],
                 affiliation = "ABC University")

我获得了 Google 学者 ID，没有任何问题。

可重现的例子：

# list from top h-index researchers (just for the purpose of this sample)

Last.Name <- c("Colditz", "Lander", "Akira", "Langer", "Karin")
First.Name <- c("Graham", "Eric", "Shizuo", "Robert", "Michael")
df <- data.frame(Last.Name, First.Name)
print (df)


library(scholar)

#First try: 
for(i in 1:3){
  
  scholars<-get_scholar_id(last_name = df$Last.Name[i], 
                           first_name = df$First.Name[i])
}

#Error: Error in tables[[1]] : subscript out of bounds


#Suggestion by @akrun

for(i in seq_along(df$Last.Name)){
  
  scholars<-get_scholar_id(last_name = df$Last.Name[i], 
                           first_name = df$First.Name[i])
}

#Error: Error in tables[[1]] : subscript out of bounds

#This way works, but not with the for function: 

scholars<-get_scholar_id(last_name = df$Last.Name[3], 
                           first_name = df$First.Name[3])
print(scholars)
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1 回答 1

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某些元素没有学者 ID，并且返回错误。tryCatch一种选择是使用or possibly(from purrr)绕过这些情况

library(purrr)
library(scholar)
p_get_scholar_id <- possibly(get_scholar_id, otherwise = NA_character_)
scholars <- character(nrow(df))
for(i in seq_along(scholars)) {
  scholars[i] <- p_get_scholar_id(last_name = df$Last.Name[i], 
                       first_name = df$First.Name[i])
  }

-输出

scholars
#[1] NA             "LXVfPc8AAAAJ" "0TG2laoAAAAJ" NA             "xVvyb1gAAAAJ"
于 2021-03-03T18:03:43.113 回答