4

所以我找到了一些答案，一个说可以这样做，另一个说不能。这让我很困惑，因为当我尝试这样做时 - 我失败了。

我想要的是在这样的子图中引用命名实体图：

@Entity
@Table(name = "parent")
@NamedEntityGraphs({
    @NamedEntityGraph(
        name = "Parent.all",
        attributeNodes = {
            @NamedAttributeNode(value = "child", subgraph = "Child.all"), // here I am referencing graph specified in Child entity
        }
    )
})
public class ParentModel {

  @OneToOne(
      mappedBy = "parent",
      fetch = FetchType.LAZY, cascade = CascadeType.ALL, orphanRemoval = true)
  private ChildModel child;

}

@Entity
@Table(name = "child")
@NamedEntityGraphs({
    @NamedEntityGraph(
        name = "Child.all",
        attributeNodes = {
            @NamedAttributeNode(value = "grandChildren"),
        }
    )
})
public class ChildModel {

  @OneToOne(fetch = FetchType.LAZY)
  @JoinColumn(name = "parent_id")
  private ParentModel parent;

  @OneToMany(
      mappedBy = "child",
      fetch = FetchType.LAZY, cascade = CascadeType.ALL, orphanRemoval = true)
  private Set<GrandChild> grandChildren;

}

我想使用 Spring Data 存储库方法：

@EntityGraph(value = "Parent.all")
List<ParentAll> findAll();

但是当我想引用grandChildren类似的东西时，我仍然会收到 LazyInitializationException parent.child.grandChildren（注意，只要我手动将 @NamedSubgraph 添加到父实体 - 一切正常）。那么是否可以这样做以使代码更清晰而不重复自己？我在这里错过了什么吗？

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0 回答 0