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我在弄清楚这一点时遇到了一些问题。我有两个查询需要放在一起，无论我尝试了什么，我总是以 mysql 语法错误告终。这两个查询如下。

查询 1 - 这是针对加拿大邮政编码的

SELECT ta.city, ta.email_address, ta.country_code, COUNT(*)
FROM jos_form_submitteddata_form1 tb
JOIN jos_postalzip_redirect ta ON UPPER(LEFT(tb.FIELD_24, 3)) = LEFT(ta.postal_zip, 3)
WHERE LENGTH(tb.FIELD_24) > 5
GROUP BY ta.city;

查询 2 - 如果是美国邮政编码

SELECT ta.city, ta.email_address, ta.country_code, COUNT(*)
FROM jos_form_submitteddata_form1 tb
JOIN jos_postalzip_redirect ta ON UPPER(tb.FIELD_24) = LEFT(ta.postal_zip, 5)
WHERE LENGTH(tb.FIELD_24) <= 5
GROUP BY ta.city
HAVING ta.country_code = 'US';

目标是让这两个查询以正确的计数显示在同一个表中

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2 回答 2

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UNION 不能满足您的需求？

SELECT ta.city, ta.email_address, ta.country_code, COUNT(*) 
FROM jos_form_submitteddata_form1 tb 
JOIN jos_postalzip_redirect ta ON UPPER(LEFT(tb.FIELD_24, 3)) = LEFT(ta.postal_zip, 3)
WHERE LENGTH(tb.FIELD_24) > 5 GROUP BY ta.city
UNION
SELECT ta.city, ta.email_address, ta.country_code, COUNT(*) 
FROM jos_form_submitteddata_form1 tb 
JOIN jos_postalzip_redirect ta ON UPPER(tb.FIELD_24) = LEFT(ta.postal_zip, 5) 
WHERE LENGTH(tb.FIELD_24) <= 5 AND ta.country_code = 'US' GROUP BY ta.city
于 2011-07-08T17:49:15.003 回答
0

尝试使用 UNION 语句。

http://dev.mysql.com/doc/refman/5.0/en/union.html

于 2011-07-08T17:50:13.917 回答