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我创建了一个运行良好的 SQL Server 层次结构。

但是，我在需要十进制加法的层次结构级别数据类型处理中遇到问题。

我试过下面的这个查询可以添加小数并完美地工作。

SELECT
    CAST('4.1' AS DEC(3,1)) + CAST('0.1' AS DEC(3,1)) ; --correct result: 4.02

但是，在我的 CTE 层次结构查询中，我收到了如下所示的错误。我认为错误是一致的：

 CAST(parent.[OWNER LEVEL] AS DEC(3,1)) + CAST(0.1 AS DEC(3,1)) AS [OWNER LEVEL],

错误：

SQL 错误 [240] [S0001]：递归查询“CTE1”的“OWNER LEVEL”列中的锚点和递归部分之间的类型不匹配。

代码：

WITH CTE1 AS 
( 
    SELECT 
        CAST('4.1' AS DEC(3,1)) as [OWNER LEVEL],
        [OWNER ID], 
        [OWNER NAME],
        CAST('4.2' AS DEC(3,1)) as [OWNED LEVEL],
        [OWNED ID], 
        [OWNED NAME]
    FROM 
        OWNER_OWNED
    
    UNION ALL
    
    SELECT 
        CAST(parent.[OWNER LEVEL] AS DEC(3,1)) + CAST(0.1 AS DEC(3,1)) AS [OWNER LEVEL],
        child.[OWNER ID], 
        child.[OWNER NAME],
        CAST(parent.[OWNED LEVEL] AS DEC(3,1)) + CAST(0.1 AS DEC(3,1)) AS [OWNED LEVEL],
        child.[OWNED ID], 
        child.[OWNED NAME]
    FROM 
        OWNER_OWNED child
    INNER JOIN 
        CTE1 parent ON parent.[OWNED ID] = child.[OWNER ID] 
)
SELECT * FROM CTE1
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1 回答 1

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每次您有一个递归查询和一个使用任何类型的运算符（加法、连接...）“吸收”许多值的列时，您必须将锚值强制转换为数据类型的最大值。

在您的情况下，将锚查询中的 [OWNER LEVEL] 转换为 DECIMAL(38,2)。

于 2021-02-17T08:31:25.220 回答