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你如何扩展JsonResult?假设我想做一个JsonTransactionResult,因为我想强制我的所有事务返回一个 jsonifiedTransactionResult对象。该TransactionResult对象包含错误消息和内容的数据。我是通过继承还是包装来做到这一点JsonResult

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1 回答 1

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我只是从 JsonResult 继承并返回TransactionResult该类的一个实例。

我有类似的东西,虽然我从 ActionResult 继承并使用 JSON.NET,因为我在使用内置 JsonResult 的 DateTime 方面遇到了一些序列化问题。

/// <summary>
/// A Newtonsoft.Json based JsonResult for ASP.NET MVC
/// </summary>
public class JsonNetResult : ActionResult
{
    /// <summary>
    /// Initializes a new instance of the <see cref="JsonNetResult"/> class.
    /// </summary>
    public JsonNetResult()
    {
        this.SerializerSettings = new JsonSerializerSettings();
    }

    /// <summary>
    /// Gets or sets the content encoding.
    /// </summary>
    /// <value>The content encoding.</value>
    public Encoding ContentEncoding { get; set; }

    /// <summary>
    /// Gets or sets the type of the content.
    /// </summary>
    /// <value>The type of the content.</value>
    public string ContentType { get; set; }

    /// <summary>
    /// Gets or sets the data.
    /// </summary>
    /// <value>The data object.</value>
    public object Data { get; set; }

    /// <summary>
    /// Gets or sets the serializer settings.
    /// </summary>
    /// <value>The serializer settings.</value>
    public JsonSerializerSettings SerializerSettings { get; set; }

    /// <summary>
    /// Gets or sets the formatting.
    /// </summary>
    /// <value>The formatting.</value>
    public Formatting Formatting { get; set; }

    /// <summary>
    /// Enables processing of the result of an action method by a custom type that inherits from the <see cref="T:System.Web.Mvc.ActionResult"/> class.
    /// </summary>
    /// <param name="context">The context in which the result is executed. The context information includes the controller, HTTP content, request context, and route data.</param>
    public override void ExecuteResult(ControllerContext context)
    {
        if (context == null)
        {
            throw new ArgumentNullException("context");
        }

        HttpResponseBase response = context.HttpContext.Response;

        response.ContentType = !String.IsNullOrWhiteSpace(this.ContentType) ? this.ContentType : "application/json";

        if (this.ContentEncoding != null)
        {
            response.ContentEncoding = this.ContentEncoding;
        }

        if (this.Data != null)
        {
            JsonTextWriter writer = new JsonTextWriter(response.Output) { Formatting = this.Formatting };

            JsonSerializer serializer = JsonSerializer.Create(this.SerializerSettings);
            serializer.Serialize(writer, this.Data);

            writer.Flush();
        }
    }
}

然后我从那个类继承,用结果包装一个成功属性:

/// <summary>
/// Derives from <see cref="JsonNetResult"/>. This action result can be used to wrap an AJAX callback result with a status code and a description, along with the actual data.
/// </summary>
public class CallbackJsonResult : JsonNetResult
{
    /// <summary>
    /// Initializes a new instance of the <see cref="CallbackJsonResult"/> class.
    /// </summary>
    /// <param name="statusCode">The status code.</param>
    public CallbackJsonResult(HttpStatusCode statusCode)
    {
        this.Initialize(statusCode, null, null);
    }

    /// <summary>
    /// Initializes a new instance of the <see cref="CallbackJsonResult"/> class.
    /// </summary>
    /// <param name="statusCode">The status code.</param>
    /// <param name="description">The description.</param>
    public CallbackJsonResult(HttpStatusCode statusCode, string description)
    {
        this.Initialize(statusCode, description, null);
    }

    /// <summary>
    /// Initializes a new instance of the <see cref="CallbackJsonResult"/> class.
    /// </summary>
    /// <param name="statusCode">The status code.</param>
    /// <param name="data">The callback result data.</param>
    public CallbackJsonResult(HttpStatusCode statusCode, object data)
    {
        this.Initialize(statusCode, null, data);
    }

    /// <summary>
    /// Initializes a new instance of the <see cref="CallbackJsonResult"/> class.
    /// </summary>
    /// <param name="statusCode">The status code.</param>
    /// <param name="description">The description.</param>
    /// <param name="data">The callback result data.</param>
    public CallbackJsonResult(HttpStatusCode statusCode, string description, object data)
    {
        this.Initialize(statusCode, description, data);
    }

    /// <summary>
    /// Initializes this instance.
    /// </summary>
    /// <param name="statusCode">The status code.</param>
    /// <param name="description">The description.</param>
    /// <param name="data">The callback result data.</param>
    private void Initialize(HttpStatusCode statusCode, string description, object data)
    {
        Data = new { Success = statusCode == HttpStatusCode.OK, Status = (int)statusCode, Description = description, Data = data };
    }
}
于 2011-07-08T07:02:01.047 回答