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我是 Python、Django 和 DRF 的新手，但我已经阅读了设置基本 REST 服务器所需的所有教程，对于这个示例，我们假设它只服务一件事：客户列表。此外，我已经安装django-simple-history并注册了我的Customer模型。

这是我迄今为止编写的代码，一切似乎都运行良好。

api/urls.py

from django.urls import path, include
from rest_framework import routers
import api.views as views

router = routers.DefaultRouter(trailing_slash=False)

router.register('customers', views.CustomerView)
router.register('customerhistory', views.CustomerHistoryView)

urlpatterns = [
    path('', include(router.urls)),
]

api/views.py

from rest_framework import viewsets
from retail.models.customers import Customer

class CustomerView(viewsets.ModelViewSet):
    queryset = Customer.objects.all()
    serializer_class = CustomerSerializer
    filterset_fields = '__all__'
    search_fields = ['name']


class CustomerHistoryView(viewsets.ModelViewSet):
    queryset = Customer.history.all()
    serializer_class = CustomerHistorySerializer
    filterset_fields = '__all__'

api/serializers.py

from rest_framework import serializers
from retail.models.customers import Customer

class CustomerSerializer(serializers.ModelSerializer):
    class Meta:
        model = Customer
        fields = '__all__'


class CustomerHistorySerializer(serializers.ModelSerializer):
    class Meta:
        model = Customer.history.model
        fields = '__all__'

实际上，当我转到 时api/customerhistory/1，它为我提供了客户 1 的所有历史记录的可爱列表。

问题

我想要做的是访问相同的列表api/customer/1/history。

到目前为止我的尝试...

为此，我将删除CustomerHistoryView并在类中添加额外的操作CustomerView。

api/views.py

from rest_framework import viewsets
from rest_framework.decorators import action
from rest_framework.response import Response
from retail.models.customers import Customer

class CustomerView(viewsets.ModelViewSet):
    queryset = Customer.objects.all()
    serializer_class = CustomerSerializer
    filterset_fields = '__all__'
    search_fields = ['name']

    @action(detail=True)
    def history(self):
        history = Customer.history.all()
        serializer = CustomerHistorySerializer(history, many=True)
        return Response(serializer.data)

这会产生以下错误：

Exception Type: TypeError at /api/customers/1/history
Exception Value: history() got multiple values for argument 'pk'

我究竟做错了什么？

4

1 回答 1

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看起来您的history方法缺少参数。

这是有关视​​图集的额外操作的文档。

@action(detail=True)
def history(self, request, pk=None):
    history = Customer.history.all()
    # ...

注意额外的参数request和pk=Noneto history。

于 2021-02-11T19:53:31.683 回答