3

查询时很容易得到联系人图片 People.CONTENT_URI，只需一个简单的 

People.loadContactPhoto(activity, ContentUris.withAppendedId(People.CONTENT_URI, contactId)

因为我知道联系人 ID。现在我需要在访问通话记录后做同样的事情。和：

String[] strFields = {
                android.provider.CallLog.Calls.CACHED_NAME,
                android.provider.CallLog.Calls.NUMBER, 
                };

        String strUriCalls="content://call_log/calls"; 

            Uri UriCalls = Uri.parse(strUriCalls); 

            Cursor cursorLog = this.getContentResolver().query(UriCalls, strFields, null, null, null);

我从通话记录中获取列表，但我找不到任何方法将其与加载照片所需的联系人 ID 链接。该应用程序从 api 级别 4+ 开始工作。

任何帮助表示赞赏。谢谢你。

正如下面的克里斯蒂安所指导的，对我有用的解决方案是：

 private long getContactIdFromNumber(String number) {
        String[] projection = new String[]{Contacts.Phones.PERSON_ID};
        Uri contactUri = Uri.withAppendedPath(Contacts.Phones.CONTENT_FILTER_URL,Uri.encode(number));
        Cursor c = getContentResolver().query(contactUri, projection, null, null, null);

        if (c.moveToFirst()) {
            long contactId=c.getLong(c.getColumnIndex(Contacts.Phones.PERSON_ID));
            return contactId;
        }
        return -1;
    }
4

5 回答 5

8

然后，您必须尝试使用​​查询的通话记录字段来获取联系人 ID。所以，你可以实现这样的事情：

private String getContactIdFromNumber(String number) {
    String[] projection = new String[]{Contacts.Phones._ID};
    Uri contactUri = Uri.withAppendedPath(Contacts.Phones.CONTENT_FILTER_URL,
        Uri.encode(number));
    Cursor c = getContentResolver().query(contactUri, projection,
        null, null, null);
    if (c.moveToFirst()) {
        String contactId=c.getString(c.getColumnIndex(Contacts.Phones._ID));
        return contactId;
    }
    return null;
}

然后，您可以使用该联系人 ID 获取照片。在你的情况下是这样的：

cursorLog.moveToFirst();
String number = cursorLog.getString(cursorLog.getColumnIndex(android.provider.CallLog.Calls.NUMBER));
contactId = getContactIdFromNumber(number)
People.loadContactPhoto(activity, ContentUris.withAppendedId(People.CONTENT_URI, contactId);
// blah blah blah
于 2011-07-07T17:48:32.950 回答
1

这个对我来说很好用..

private void contactPickedFromLog(Intent data) {
    // TODO Auto-generated method stub
    String contactNumber = data.getStringExtra(CONTACT_NUMBER);
    Cursor cursor = getContentResolver().query(
            Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI,
                    Uri.decode(contactNumber)),
            new String[] { PhoneLookup._ID }, null, null, null);
    if(cursor.moveToFirst()){
    long contactId = cursor.getLong(0);
    InputStream inputStream = Contacts.openContactPhotoInputStream(
            getContentResolver(),
            ContentUris.withAppendedId(Contacts.CONTENT_URI, contactId));
    if(inputStream!=null)
    Bitmap bitmap = BitmapFactory.decodeStream(inputStream);
    }
}
于 2012-02-08T22:38:23.663 回答
0

我这样做是这样的：

ContentResolver cr=this.getContentResolver();
Cursor cc = cr.query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
while (cc.moveToNext())
{
    contactId = cc.getString(cc.getColumnIndex(ContactsContract.Contacts._ID));
    Uri contactPhotoUri = ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, Long.parseLong(contactId));
    InputStream is=ContactsContract.Contacts.openContactPhotoInputStream(cr, contactPhotoUri);
    //blah-blah
}
于 2011-07-07T17:54:47.897 回答
0

尝试这个 ...

public Bitmap getPhoto(String phoneNumber) {
    Uri phoneUri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber));
    Uri photoUri = null;
    ContentResolver cr = getContentResolver();
    Cursor contact = cr.query(phoneUri,
            new String[] { ContactsContract.Contacts._ID }, null, null, null);

    if (contact.moveToFirst()) {
        long userId = contact.getLong(contact.getColumnIndex(ContactsContract.Contacts._ID));
        photoUri = ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, userId);

    }
    else {
        Bitmap defaultPhoto = BitmapFactory.decodeResource(getResources(), R.drawable.ic_contact_picture);
        return getCircleBitmap(defaultPhoto);
    }
    if (photoUri != null) {
        InputStream input = ContactsContract.Contacts.openContactPhotoInputStream(
                cr, photoUri);
        if (input != null) {
            return getCircleBitmap(BitmapFactory.decodeStream(input));
        }
    } else {
        Bitmap defaultPhoto = BitmapFactory.decodeResource(getResources(), R.drawable.ic_contact_picture);
        return getCircleBitmap(defaultPhoto);
    }
    Bitmap defaultPhoto = BitmapFactory.decodeResource(getResources(), R.drawable.ic_contact_picture);
    contact.close();
    return defaultPhoto;
}
于 2016-08-17T08:56:16.483 回答
0

以上答案都是正确的。您也可以通过此获取照片...

c.getString(c.getColumnIndex(CallLog.Calls.CACHED_PHOTO_URI));

在 SDK >=23 中工作

如果您使用最低 SDK...

Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(num));
        uri = ((phone_uri != null) ? Uri.parse(phone_uri) : uri);
        Cursor cursor = getContext().getContentResolver().query(uri, null, null, null, null);

        if (cursor != null) {
            if (cursor.moveToNext()) {
                String id = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup._ID));
                String name = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
                image_uri = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.PHOTO_URI));
                Log.d(TAG, "name " + name + " id "+id+" image_uri "+ image_uri);
            }
            cursor.close();
        }
于 2017-12-30T05:34:55.113 回答