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目前我正在做一个需要在服务器数据库上发布数据的项目。在这里，我发布了name, id,image等数据。

我想将图像作为二进制数据传递。为此，我将图像转换为 base64 字符串，然后 POST 数据，但由于图像分辨率或 HTTP 连接大小较大，我收到 413 错误代码，表明 URL 太大。

请问谁能给我解决方案？在这里，我给你我已经实现的代码。

价值观

Bitmap b1 = (Bitmap) data.getExtras().get("data");
b1=Bitmap.createScaledBitmap(b1, 100,100, true);
ByteArrayOutputStream baos = new ByteArrayOutputStream();  
b1.compress(Bitmap.CompressFormat.JPEG, 100, baos); 
byte[] b = baos.toByteArray(); 
String base64String = Base64.encodeBytes(b);

Log.e("Base 64 conversion of image--------", base64String);

response = webService.doNetworkConnection("{\"method\":\"EventUploadPhoto\",\"data\":{\"ClientCode\":"
    + "\""
    + Util.clientCode
    + "\""
    + ",\"EventID\":"
    + "\""
    + itemId
    + "\""
    + ",\"ImageName\":"
    + "\""
    + filename
    + System.currentTimeMillis()
    + "\""
    + ",\"ImageData\":"
    + "\""
    + imgData
    + "\""
    + ",\"UserName\":"
    + "\""
    + username
    + "\""
    + ",\"TokenId\":"
    + "\""
    + tokenid
    + "\"" + "}}", "POST");

做网络连接

public String doNetworkConnection(String request, String methodType) throws IOException {
    String str = java.net.URLEncoder.encode(request, "UTF-8");
    String resultstring = "";
    System.out.println("string request:" + request);

    int response = -1;

    try {
        URL url = new URL((mContext.getResources()
                        .getString(R.string.WebServiceUrl))
                        + "" + str);
        System.out.println("url:" + url);
        URLConnection conn = url.openConnection();

        HttpURLConnection httpConn = (HttpURLConnection) conn;
        httpConn.setAllowUserInteraction(false);
        httpConn.setInstanceFollowRedirects(true);
        httpConn.setRequestProperty("Content-Type","application/x-www-form-urlencoded");
        httpConn.connect();

        response = httpConn.getResponseCode();
        System.out.println("response code:" + response);

        if (response == HttpURLConnection.HTTP_OK) {
            InputStream is = httpConn.getInputStream();
            resultstring = convertinputStreamToString(is);
        } else {
            resultstring = "";             
        }
    } catch (Exception e) {
        resultstring = "";         
    }   
    System.out.println("result string:" + resultstring);

    return resultstring;
}

这里的 HTTP 响应代码是 413，所以它告诉 URL 太大，不能 POST 图像。

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1 回答 1

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如果您设置在 HTTP：因为它只是一个字符串，您可以将其分解为单独的字符串并单独发布它们。然后在另一边将它们连接在一起。

否则，您可以使用 FTP 或降低并通过 TCP/IP 流式传输它。有像这样的 Java 库。

于 2011-07-06T12:58:15.670 回答