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我对这段代码有疑问。这是扫雷游戏。游戏很好，但是当我将光标移到游戏窗口外时，整个棋盘都显示给我了。怎么解决，有大佬知道吗？你能帮我解决这个问题吗？我认为问题可能是检查光标位置或表格的填充方式。

#include<SFML/Graphics.hpp>
#include<time.h>

using namespace sf;


int main()
{
    srand(time(0));

    RenderWindow app(VideoMode(400, 400), "Start The Minesweeper");

    int w = 32;
    int grid[12][12];
    int sgrid[12][12]; // For showing the grid

    Texture t;
    t.loadFromFile("images/tiles.jpg");
    Sprite s(t);

    for(int i = 1; i<=10; i++)
        for (int j = 1; j <= 10; j++) {
            sgrid[i][j] = 10;

            if (rand() % 5 == 0) grid[i][j] = 9;
            else grid[i][j] = 0;
        }

    for (int i = 1; i <= 10; i++)
        for (int j = 1; j <= 10; j++) {
            int n = 0;
            if (grid[i][j] == 9) continue;
            if (grid[i + 1][j] == 9) n++;
            if (grid[i][j + 1] == 9) n++;
            if (grid[i - 1][j] == 9) n++;
            if (grid[i][j - 1] == 9) n++;

            if (grid[i + 1][j + 1] == 9) n++;
            if (grid[i - 1][j - 1] == 9) n++;
            if (grid[i - 1][j + 1] == 9) n++;
            if (grid[i + 1][j - 1] == 9) n++;

            grid[i][j] = n;
        }

    while (app.isOpen())
    {
        Vector2i pos = Mouse::getPosition(app);
        int x = pos.x / w;
        int y = pos.y / w;

        Event e;
        while (app.pollEvent(e))
        {
            if (e.type == Event::Closed)
                app.close();

            if (e.type == Event::MouseButtonPressed)
                if (e.key.code == Mouse::Left) sgrid[x][y] = grid[x][y];
                else if (e.key.code == Mouse::Right) sgrid[x][y] = 11;

        }

        app.clear(Color::White);
        for (int i = 1; i <= 10; i++)
            for (int j = 1; j <= 10; j++) {

                if (sgrid[x][y] == 9) sgrid[i][j] = grid[i][j];

                s.setTextureRect(IntRect(sgrid[i][j] * w, 0, w, w));
                s.setPosition(i * w, j * w);
                app.draw(s);
            }

        app.display();
        


    }


    
}

此代码的图像

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1 回答 1

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无论是否按下鼠标按钮，您似乎都在更新 x 和 y 网格位置，在这一行：

if (sgrid[x][y] == 9) sgrid[i][j] = grid[i][j];

此外，看起来您正在检查显示sgrid[x][y]而不是grid[x][y]鼠标单击位置的数据。

您最可能想要做的是在单击鼠标按钮时添加一个标志，并且仅在单击按钮时检查地雷。我在下面的代码中做了一些小改动，试一试：

#include<SFML/Graphics.hpp>
#include<time.h>

using namespace sf;


int main()
{
    srand(time(0));

    RenderWindow app(VideoMode(400, 400), "Start The Minesweeper");

    int w = 32;
    int grid[12][12];
    int sgrid[12][12]; // For showing the grid

    Texture t;
    t.loadFromFile("images/tiles.jpg");
    Sprite s(t);

    for(int i = 1; i<=10; i++)
        for (int j = 1; j <= 10; j++) {
            sgrid[i][j] = 10;

            if (rand() % 5 == 0) grid[i][j] = 9;
            else grid[i][j] = 0;
        }

    for (int i = 1; i <= 10; i++)
        for (int j = 1; j <= 10; j++) {
            int n = 0;
            if (grid[i][j] == 9) continue;
            if (grid[i + 1][j] == 9) n++;
            if (grid[i][j + 1] == 9) n++;
            if (grid[i - 1][j] == 9) n++;
            if (grid[i][j - 1] == 9) n++;

            if (grid[i + 1][j + 1] == 9) n++;
            if (grid[i - 1][j - 1] == 9) n++;
            if (grid[i - 1][j + 1] == 9) n++;
            if (grid[i + 1][j - 1] == 9) n++;

            grid[i][j] = n;
        }

    while (app.isOpen())
    {
        Vector2i pos = Mouse::getPosition(app);
        int x = pos.x / w;
        int y = pos.y / w;
        bool mbleft = false;

        Event e;
        while (app.pollEvent(e))
        {
            if (e.type == Event::Closed)
                app.close();

            if (e.type == Event::MouseButtonPressed)
                if (e.key.code == Mouse::Left)
                {
                    sgrid[x][y] = grid[x][y];
                    mbleft = true;
                }
                else if (e.key.code == Mouse::Right) sgrid[x][y] = 11;

        }

        app.clear(Color::White);
        for (int i = 1; i <= 10; i++)
            for (int j = 1; j <= 10; j++) {

                if (mbleft && sgrid[x][y] == 9) sgrid[i][j] = grid[i][j];

                s.setTextureRect(IntRect(sgrid[i][j] * w, 0, w, w));
                s.setPosition(i * w, j * w);
                app.draw(s);
            }

        app.display();
        


    }


    
}
于 2021-01-29T21:13:37.233 回答