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我必须从待办事项列表应用程序中随机选择一个元素并单击以将其删除。基本上，每个元素都有相同的选择器，只是索引更改（例如//*[@class="destroy"])[2]）。我有生成随机句子并将它们添加到应用程序的代码。然后我必须随机选择一个元素->单击它以删除，然后我就卡住了。Random.choice 选择一个随机数，实际上它可以工作。但有时如果它随机选择 [0] 测试失败并且测试执行需要大量时间，我相信有更专业的方法来进行随机选择。您能否建议其他可能的方法？

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver import ActionChains
import random
import os
 
@keyword
    def open_browser(self):
        os.environ['MOZ_HEADLESS'] = '1'
        self.driver = webdriver.Firefox()
        self.driver.get('http://todomvc.com/examples/react/#/')
        self.driver.implicitly_wait(20)
@keyword
    def generate_random_sentences(self, number, total_items_amount):
        words = [["One", "Two", "Three", "Four"], ["red", "yellow", "green", "blue"],
                 ["cats", "dogs", "zebras", "pandas"], ["jumped.", "danced.", "wrote poetry.", "cried."]]
        for i in range(int(number)):
            sentences = ' '.join([random.choice(w) for w in words])
            self.driver.find_element(By.CLASS_NAME, "new-todo").send_keys(sentences, Keys.ENTER)
        total_items = self.driver.find_element(By.CLASS_NAME, "todo-count")
        assert total_items.text == total_items_amount```

@keyword
    def delete_random_element(self, total_items_amount):
        i = random.choice(range(51))
        list_item = self.driver.find_element(By.XPATH, '(//*[@class="view"]){}'.format([i])) 
        hidden_button = self.driver.find_element(By.XPATH, '(//*[@class="destroy"]){}'.format([i])) 
        actions = ActionChains(self.driver)
        actions.move_to_element(list_item)
        actions.click(hidden_button)
        actions.perform()
        total_items = self.driver.find_element(By.CLASS_NAME, "todo-count")
        assert total_items.text == total_items_amount```
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1 回答 1

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您可以使用random.randint(start, end)指定可以随机选择的整数范围并将其作为索引传递。

random_element = f'//*[@class="destroy"])[{random.randint(startint,endint)}]'
于 2021-01-21T21:19:34.183 回答