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我对 sympy 有疑问，我有一个必须用公式计算的数据框列，并且公式是字符串格式我使用的是 sympy，它只取一个值，而不是我的代码

    import sympy
    def eval_eqn(eqn,in_dict):
        sub = {sympy.symbols(key):item for key,item in in_dict.items()}
        ans = sympy.simplify(eqn).evalf(subs = sub)
        
    
        return ans
    in_dict = {"x": df['bike_count'],"y":df['car_count'],"z":df['flight_count']}
    eqn = "x+y+z"
    eval_eqn(eqn,in_dict)

当我使用这个得到一个错误说这个系列必须属性。有func什么建议吗？

4

1 回答 1

1

我对你的代码做了一些小的改动。以下是更新版本。请根据您的需要进行更改。


from sympy import *
import pandas as pd 
  
# initialize list of lists 
data = [[10, 15, 14]] 
  
# Create the pandas DataFrame 
df = pd.DataFrame(data, columns = ['bike_count', 'car_count','flight_count']) 
print(df)
def eval_eqn(eqn,in_dict):
    sub = {symbols(key):item for key,item in in_dict.items()}
    ans = simplify(eqn).evalf(subs = sub)
    

    return ans
in_dict = {"x": df['bike_count'],"y":df['car_count'],"z":df['flight_count']}
x, y, z = symbols("x y z")
eqn = x+y+z
print(eval_eqn(eqn,in_dict))

编辑了对 df 中多个值的评论

from sympy import *
import pandas as pd 
  
# initialize list of lists 
data = [[10, 15, 14],[20, 15, 14]] 
  
# Create the pandas DataFrame 
df = pd.DataFrame(data, columns = ['bike_count', 'car_count','flight_count']) 
print(df)
def eval_eqn(eqn,in_dict):
    sub = {symbols(key):item for key,item in in_dict.items()}
    print(sub)
    #exit()
    ans = simplify(eqn).evalf(subs = sub)
    

    return ans
in_dict = {"x": df['bike_count'],"y":df['car_count'],"z":df['flight_count']}
#print("ddd",in_dict)
x, y, z = symbols("x y z")
eqn = x+y+z
for index, row in df.iterrows():
    print({"x": row['bike_count'],"y":row['car_count'],"z":row['flight_count']})
    print(eval_eqn(eqn,{"x": row['bike_count'],"y":row['car_count'],"z":row['flight_count']}))

请查看它，如果您需要更多帮助，请告诉我。:)

于 2021-01-18T12:08:26.780 回答