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我正在尝试解压缩多个参数包，以便arr[i][j] = X(i,j). 但是，使用下面的当前方法出现以下错误。有没有使用 C++14/17 实现上述目标的方法？

// Non copyable and default constructable
struct X
{
    X(const X&) = delete;
    X(int x, int y) : _x(x), _y(y)
    {}
    int _x;
    int _y;
};

X getX(int i, int j)
{
    return X(i,j);
}


template <std::size_t ...Xidx, std::size_t ... Yidx>
auto make_2d_array(std::index_sequence<Xidx...>, std::index_sequence<Yidx...>)
{
    std::array<std::array<X,sizeof...(Xidx)>, sizeof...(Yidx)> arr = {getX(Xidx, Yidx)...};
    return arr;
}

static constexpr std::size_t M = 5;
static constexpr std::size_t N = 6;

int main()
{
    std::array<std::array<X,M>, N> arr = make_2d_array(std::make_index_sequence<M>{}, std::make_index_sequence<N>{});
}

错误

<source>:26:87: error: pack expansion contains parameter packs 'Xidx' and 'Yidx' that have different lengths (5 vs. 6)
    std::array<std::array<X,sizeof...(Xidx)>, sizeof...(Yidx)> arr = {getX(Xidx, Yidx)...};
                                                                           ~~~~  ~~~~ ^
<source>:35:42: note: in instantiation of function template specialization 'make_2d_array<0, 1, 2, 3, 4, 0, 1, 2, 3, 4, 5>' requested here
    std::array<std::array<X,M>, N> arr = make_2d_array(std::make_index_sequence<M>{}, std::make_index_sequence<N>{});
                                         ^
1 error generated.
Compiler returned: 1
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1 回答 1

1

我会这样做

template<std::size_t... XIs, std::size_t... YIs>
std::array<std::array<X, sizeof...(XIs)>, sizeof...(YIs)> make_2d_array(std::index_sequence<XIs...>, std::index_sequence<YIs...>)
{
    return {
        [](auto YI) -> std::array<X, sizeof...(XIs)> {
            return {getX(XIs, YI)...};
        }(YIs)...
    };
}

是的，这有点可怕。原理很简单，我们需要在语法上分开XIs并且YIs足够，每个...扩展只解包其中一个，我们需要两个扩展来做“产品”而不是“压缩”。

于 2021-01-07T06:40:55.767 回答