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我在 Python“lines_origin”和“lines_dest”中有两个元组以一种可能非常低效的方式生成！但是它们显示了连接：lines_origin[1] 连接到lines_dest[2] 等等。

我需要做的是，分别遍历所有可能坐标的单独“主”列表，返回其连接的点，然后根据另一个状态列表（开/关）检查该连接子列表。到目前为止，这是我的尝试：

import random
import numpy as np

### my list of all points
coordinates = []
for x in range(10):
    for y in range(20):
        coordinates.append((x,y))

### the connections between points
lines = []
while len(lines) < (800): # limiting each point to an average of 4 connections
    rnd_pair = random.sample(coordinates, 2)
    rnd_pair_rev = [rnd_pair[1],rnd_pair[0]]
    rnd_pair_x = [x for x,y in rnd_pair]
    rnd_pair_y = [y for x,y in rnd_pair]
    distance = abs(rnd_pair_x[0] - rnd_pair_x[1]) + abs(rnd_pair_y[0] - rnd_pair_y[1])
    if distance <=2:
        if rnd_pair not in lines and rnd_pair_rev not in lines:
            lines.append(rnd_pair)
    else:
        rnd_pair = []
        rnd_pair_rev = []
        rnd_pair_x = []
        rnd_pair_y = []

### splitting the connections into two tuples
lines_origin, lines_dest = zip(*lines)

### an array of binary statuses, these line up to coordinates by index (so if 
  # states[6] = "ON" then this denotes that coordinates[6] is on. 
states = np.random.choice(["ON", "OFF"], size = len(coordinates), replace=True, p=[0.2, 0.8])

### my failed attempt to iterate over the coordinates
for i in coordinates:
    if coordinates[i] in lines_origin:
        connections = lines_dest # this should return the coordinates of the points that coordinates[i] 
                                 # is connected to
    if coordinates[i] in lines_dest:
        connections.append(lines_origin) # as above but checking the destination points
    list(set(connections)) # dedupe the connections
    ### check whether a point is connected to an "ON" point
    for point in connections:
        return states[coordinates.index(connections[point])]
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