arrays - laravel 中如何访问数组的元素？

Question

我正在尝试计算等于某个值的元素的数量，但是当我运行时，我很难找到我想要比较的元素：

{{dd($numberofnotifications)}}

我得到以下信息：

但我需要比较的值在“属性”下

那么我如何获得属性下的值？

当我打印出数组的每个元素时，我得到以下格式：

{"id":"96a40ebb-a2d1-44d8-9600-e94dd026f152","type":"App\\Notifications\\CommentCreated","notifiable_type":"App\\User","notifiable_id":1,"data":{"comment_id":9,"data":{"name":"John","date":"2020-12-30T08:37:47.000000Z","email":"John@gmail.com","post":2,"body":"test"},"message":"John commented on your post"},"read_at":null,"created_at":"2020-12-30T08:37:47.000000Z","updated_at":"2020-12-30T08:37:47.000000Z"}

Answer 1

似乎这些项目是一个 DatabaseNotifications 数组。因此，您可以通过索引手动获取每个元素：

$numberofnotifications[0]->id;
// or
$numberofnotifications[0]->type

或者你可以使用foreach循环：

foreach ($numberofnotifications as $notification) {
    $notification->id;
}

Answer 2

由于结果是一个集合，您可以使用转换它们

$numberofnotifications->toArray();

Answer 3

您需要使用 foreach 来遍历集合：

foreach($numberofnotification as $number)
    {
        $number->name;   //name here is the "name" of the attribute you want to access
    }

如果要将它们存储在数组中，则：

foreach($numberofnotification as $number)
    {
       $attributes[]=$number->name;   //name here is the "name" of the attribute you want to access
    }

 

Answer 4

你试过这个吗

//考虑 $username 是登录的用户名

$filtered_count = $numberofnotifications->where('name', $username)->count();

如果你想要记录

$filtered = $numberofnotifications->where('name', $username)->all();