我有这张桌子
id name json
1 alex {"type": "user", "items": [ {"name": "banana", "color": "yellow"}, {"name": "apple", "color": "red"} ] }
2 peter {"type": "user", "items": [ {"name": "watermelon", "color": "green"}, {"name": "pepper", "color": "red"} ] }
3 john {"type": "user", "items": [ {"name": "tomato", "color": "red"} ] }
4 carl {"type": "user", "items": [ {"name": "orange", "color": "orange"}, {"name": "nut", "color": "brown"} ] }
重要的是,每个 json 对象可以有不同数量的“项目”,但我需要的是在 WHERE 条件中匹配的对象的“产品名称”。
我想要的输出将是前两列,只是项目的名称,其中颜色类似于 %red%:
id name fruit
1 alex apple
2 peter pepper
3 john tomato
select id, name, ***** (this is what I don't know) FROM table
where JSON_EXTRACT(json, "$.items[*].color") like '%red%'