-2

我使用 TLSharp 库。如何将我的位置发送给用户。我知道如何发送简单的短信,但不明白如何分享我的地理位置。

var store = new FileSessionStore();
            var client = new TelegramClient(api_id, api_hash, store,"session");
            await client.ConnectAsync(); 
...   
await client.SendMessageAsync(new TLInputPeerUser() { UserId = userByPhoneId.Id }, "Simple mess");

我创建请求:

        TLInputPeerUser ip = new TLInputPeerUser() { UserId = user.Id };
        
        TLInputMediaGeoPoint igp = new TLInputMediaGeoPoint();
        igp.GeoPoint = new TLInputGeoPoint() { Lat= ..., Long= ...};
        
       
        var req = new TLRequestSendMedia()
        {
            Media = igp ,
            Peer = ip,
            RandomId = 


    };

        await client.SendRequestAsync<Boolean>(req);

但这不起作用,因为需要值 RandomId。随机 ID 具有长类型,我尝试生成随机长数但没有帮助,我收到错误。

4

1 回答 1

0
var req = new TLRequestSendMedia()
            {
                Media = igp,
                Peer = ip,
                RandomId = Helpers.GenerateRandomLong()


            };

            await client.SendRequestAsync<TLAbsUpdates>(req);
于 2020-12-29T12:20:37.983 回答