我有以下 JSON 结构作为输入，可以嵌套和不嵌套。我想获取 JSON 作为 Spring Boot 应用程序中的输入和进程。如何在 JSON 中创建一个动态键值的类。它可以是 JSON 输入中的任何键值对。下面是示例之一。
没有嵌套：
{
"mappings": {
"properties": {
"firstname": {
"type": "string"
},
"lastname": {
"type": "string"
},
"salary": {
"type": "integer"
},
"date_of_birth": {
"type": "date"
}
}
}
}
嵌套：
{
"mappings": {
"properties": {
"firstname": {
"type": "string"
},
"lastname": {
"type": "string"
},
"annual_salary": {
"type": "integer"
},
"date_of_birth": {
"type": "date"
},
"comments": {
"type": "nested",
"properties": {
"name": {
"type": "string"
},
"comment": {
"type": "string"
},
"age": {
"type": "short"
},
"stars": {
"type": "short"
},
"date": {
"type": "date"
}
}
}
}
}
}
我不知道如何创建一个类来支持嵌套和不嵌套在单个类中。我尝试了以下方法。它没有帮助。
public class Schema {
Mapping mappings;
public Mapping getMappings() {
return mappings;
}
public void setMappings(Mapping mappings) {
this.mappings = mappings;
}
public static class Mapping {
Property properties;
public Property getProperties() {
return properties;
}
public void setProperties(Property properties) {
this.properties = properties;
}
}
public static class Property {
Map<String, Map<String, Object>> field = new HashMap<>();
public Map<String, Map<String, Object>> getField() {
return field;
}
public void setField(Map<String, Map<String, Object>> field) {
this.field = field;
}
}
}