我对下面显示的代码有问题。当我刚刚推送推文信息时，我的原始代码有效。一旦我编辑它以提取文本中的 URL，它就开始给我带来问题。什么都没有打印，我收到这些错误。
Traceback (most recent call last):
File "C:\Users\Evan\PycharmProjects\DiscordBot1\main.py", line 22, in <module>
get_tweets(api, "cnn")
File "C:\Users\Evan\PycharmProjects\DiscordBot1\main.py", line 18, in get_tweets
url2 = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+',
text)
File "C:\Users\Evan\AppData\Local\Programs\Python\Python39\lib\re.py", line 241, in findall
return _compile(pattern, flags).findall(string)
TypeError: cannot use a string pattern on a bytes-like object
在运行它之前我没有收到任何错误，所以我对为什么这不起作用感到非常困惑。这可能会很简单，因为我不熟悉使用 Tweepy 和 Regex。
import tweepy
import re
TWITTER_APP_SECRET = 'hidden'
TWITTER_APP_KEY = 'hidden'
auth = tweepy.OAuthHandler(TWITTER_APP_KEY, TWITTER_APP_SECRET)
api = tweepy.API(auth)
def get_tweets(api, username):
page = 1
while True:
tweets = api.user_timeline(username, page=page)
for tweet in tweets:
text = tweet.text.encode("utf-8")
url2 = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-
F]))+', text)
print(url2)
get_tweets(api, "cnn")
再次出现错误：
Traceback (most recent call last):
File "C:\Users\Evan\PycharmProjects\DiscordBot1\main.py", line 22, in <module>
get_tweets(api, "cnn")
File "C:\Users\Evan\PycharmProjects\DiscordBot1\main.py", line 18, in get_tweets
url2 = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+',
text)
File "C:\Users\Evan\AppData\Local\Programs\Python\Python39\lib\re.py", line 241, in findall
return _compile(pattern, flags).findall(string)
TypeError: cannot use a string pattern on a bytes-like object
Process finished with exit code 1
如果您需要更多信息来帮助我，请告诉我，任何帮助表示赞赏，在此先感谢。